The Ammeter and the Voltmeter — Question 6

Section 27-7 · Physics pages 4442–4443

Question 6 A voltmeter outside the ammeter includes the instrument voltage burden An ideal voltmeter spans the series combination of an unknown resistor R and an ammeter of resistance RA=2.00 ohm. The ammeter reads .200 A and the voltmeter reads 10.0 V. + − E A R V Circuit connections and marked polarities define the model; wire lengths are schematic. (a) Find R and the power actually dissipated in the specimen. (b) Derive the fractional overestimate produced by V/I and compare its useful resistance range with the arrangement that places the voltmeter only across R.
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Question 6 - Solution A voltmeter outside the ammeter includes the instrument voltage burden + − E A R V (a) Method and calculation V = I(R + RA) ⇒R = V/I −RA = 50 −2 = 48.0 Ω. PR = I2R = (.200)2(48) = 1.92 W. (b) Interpretation and further calculation Rnaive = R + RA, Rnaive −R R = RA/R. R ≫RA favors this layout; R ≪RV favors the specimen-only voltage layout. Physical check The measured product VI includes ammeter heating as well as specimen heating.

Question 6

A voltmeter outside the ammeter includes the instrument voltage burden

An ideal voltmeter spans the series combination of an unknown resistor R and an ammeter of resistance RA=2.00 ohm. The ammeter reads .200 A and the voltmeter reads 10.0 V.

Diagram shown in the original SVG worksheet.

  1. Find R and the power actually dissipated in the specimen.

  2. Derive the fractional overestimate produced by V/I and compare its useful resistance range with the arrangement that places the voltmeter only across R.

Question 6 - Solution

A voltmeter outside the ammeter includes the instrument voltage burden

Diagram shown in the original SVG worksheet.

(a) Method and calculation

V=I(R+RA)⇒R=V/I−RA=50−2=48.0Ω.V=I(R+R_A)\Rightarrow R=V/I-R_A=50-2=48.0\,\Omega.PR=I2R=(.200)2(48)=1.92W.P_R=I^2R=(.200)^2(48)=1.92\,\mathrm W.

(b) Interpretation and further calculation

Rnaive=R+RA,Rnaive−RR=RA/R.R_{\mathrm{naive}}=R+R_A,\quad\frac{R_{\mathrm{naive}}-R}{R}=R_A/R.R≫RA favors this layout; R≪RV favors the specimen-only voltage layout.R\gg R_A\text{ favors this layout; }R\ll R_V\text{ favors the specimen-only voltage layout}.

Physical check

The measured product VI includes ammeter heating as well as specimen heating.