Multiloop Circuits — Question 1

Section 27-6 · Physics pages 4412–4413

Question 1 Branch currents satisfy a junction equation and a global power balance An ideal 24.0 V source feeds parallel 6.00 ohm and 12.0 ohm resistors. All connecting wires have zero resistance. + − 24 V 6 Ω 12 Ω Circuit connections and marked polarities define the model; wire lengths are schematic. (a) Find the two branch currents, total source current and equivalent resistance. (b) Calculate the power in each resistor and verify source power equals their sum.
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Question 1 - Solution Branch currents satisfy a junction equation and a global power balance + − 24 V 6 Ω 12 Ω (a) Method and calculation I1 = 24/6 = 4.00 A, I2 = 24/12 = 2.00 A. Is = I1 + I2 = 6.00 A, Req = 24/6 = 4.00 Ω. (b) Interpretation and further calculation P1 = I2 1R1 = 96.0 W, P2 = I2 2R2 = 48.0 W. Ps = 24(6) = 144 W = P1 + P2. Physical check Equal branch voltage does not imply equal branch current.

Question 1

Branch currents satisfy a junction equation and a global power balance

An ideal 24.0 V source feeds parallel 6.00 ohm and 12.0 ohm resistors. All connecting wires have zero resistance.

Diagram shown in the original SVG worksheet.

  1. Find the two branch currents, total source current and equivalent resistance.

  2. Calculate the power in each resistor and verify source power equals their sum.

Question 1 - Solution

Branch currents satisfy a junction equation and a global power balance

Diagram shown in the original SVG worksheet.

(a) Method and calculation

I1=24/6=4.00A,I2=24/12=2.00A.I_1=24/6=4.00\,\mathrm A,\quad I_2=24/12=2.00\,\mathrm A.Is=I1+I2=6.00A,Req=24/6=4.00Ω.I_s=I_1+I_2=6.00\,\mathrm A,\quad R_{\mathrm{eq}}=24/6=4.00\,\Omega.

(b) Interpretation and further calculation

P1=I12R1=96.0W,P2=I22R2=48.0W.P_1=I_1^2R_1=96.0\,\mathrm W,\quad P_2=I_2^2R_2=48.0\,\mathrm W.Ps=24(6)=144W=P1+P2.P_s=24(6)=144\,\mathrm W=P_1+P_2.

Physical check

Equal branch voltage does not imply equal branch current.