Calculating the Current in a Single-Loop Circuit — Question 3

Section 27-3 · Physics pages 4356–4357

Question 3 Two load tests determine a source model without a voltmeter A source drives 2.00 A through a 5.00 ohm load and 1.00 A through an 11.0 ohm load. Its emf E and internal resistance r are unchanged between tests. + − E R r Circuit connections and marked polarities define the model; wire lengths are schematic. (a) Infer E and r from the loop equations. (b) Predict the current for a 2.00 ohm load and determine whether the inferred r is physically admissible.
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Question 3 - Solution Two load tests determine a source model without a voltmeter + − E R r (a) Method and calculation E = 2(5 + r), E = 1(11 + r). 10 + 2r = 11 + r ⇒r = 1.00 Ω, E = 12.0 V. (b) Interpretation and further calculation I(2.00 Ω) = 12.0/(2.00 + 1.00) = 4.00 A. r = 1.00 Ω> 0 is compatible with a passive internal resistance. Physical check Different loads supply independent constraints; one current measurement would leave E and r underdetermined.

Question 3

Two load tests determine a source model without a voltmeter

A source drives 2.00 A through a 5.00 ohm load and 1.00 A through an 11.0 ohm load. Its emf E and internal resistance r are unchanged between tests.

Diagram shown in the original SVG worksheet.

  1. Infer E and r from the loop equations.

  2. Predict the current for a 2.00 ohm load and determine whether the inferred r is physically admissible.

Question 3 - Solution

Two load tests determine a source model without a voltmeter

Diagram shown in the original SVG worksheet.

(a) Method and calculation

E=2(5+r),E=1(11+r).E=2(5+r),\quad E=1(11+r).10+2r=11+r⇒r=1.00Ω,E=12.0V.10+2r=11+r\Rightarrow r=1.00\,\Omega,\quad E=12.0\,\mathrm V.

(b) Interpretation and further calculation

I(2.00Ω)=12.0/(2.00+1.00)=4.00A.I(2.00\,\Omega)=12.0/(2.00+1.00)=4.00\,\mathrm A.r=1.00Ω>0is compatible with a passive internal resistance.r=1.00\,\Omega>0\quad\text{is compatible with a passive internal resistance}.

Physical check

Different loads supply independent constraints; one current measurement would leave E and r underdetermined.