Work, Energy, and Emf — Question 8

Section 27-2 · Physics pages 4346–4347

Question 8 Energy measurements reconstruct hidden source parameters During a 50.0 s discharge at constant current 2.00 A, a source releases 1500 J of chemical energy and delivers 1400 J to the load. Assume all missing energy heats a constant internal resistance. + − E load r Circuit connections and marked polarities define the model; wire lengths are schematic. (a) Infer emf and internal resistance. (b) Find terminal voltage and verify it through both electrical and energy relations.
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Question 8 - Solution Energy measurements reconstruct hidden source parameters + − E load r (a) Method and calculation Q = It = 100 C, E = Wchem/Q = 15.0 V. r = Wchem −Wload I2t = 100/200 = .500 Ω. (b) Interpretation and further calculation V = E −Ir = 15.0 −2(.500) = 14.0 V. V = Wload/Q = 1400/100 = 14.0 V. Physical check Independent energy and terminal relations must agree if the internal-resistance model is adequate.

Question 8

Energy measurements reconstruct hidden source parameters

During a 50.0 s discharge at constant current 2.00 A, a source releases 1500 J of chemical energy and delivers 1400 J to the load. Assume all missing energy heats a constant internal resistance.

Diagram shown in the original SVG worksheet.

  1. Infer emf and internal resistance.

  2. Find terminal voltage and verify it through both electrical and energy relations.

Question 8 - Solution

Energy measurements reconstruct hidden source parameters

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Q=It=100C,ℰ=Wchem/Q=15.0V.Q=It=100\,\mathrm C,\quad\mathcal E=W_{\mathrm{chem}}/Q=15.0\,\mathrm V.r=Wchem−WloadI2t=100/200=.500Ω.r=\frac{W_{\mathrm{chem}}-W_{\mathrm{load}}}{I^2t}=100/200=.500\,\Omega.

(b) Interpretation and further calculation

V=ℰ−Ir=15.0−2(.500)=14.0V.V=\mathcal E-Ir=15.0-2(.500)=14.0\,\mathrm V.V=Wload/Q=1400/100=14.0V.V=W_{\mathrm{load}}/Q=1400/100=14.0\,\mathrm V.

Physical check

Independent energy and terminal relations must agree if the internal-resistance model is adequate.