Power in Electric Circuits — Question 3

Section 26-6 · Physics pages 4256–4257

Question 3 Uniform charge delivery minimizes resistive loss over a fixed time A nonnegative current waveform transports prescribed charge Q through constant resistance R during time T. No other constraint is imposed. t I Axes and labels specify the model; the sketch is schematic. (a) Use ∫T 0 [I(t) −Q/T]2dt ≥0 to derive the least possible heating. (b) Compare with delivery by a constant pulse lasting only fraction f of T, with zero current otherwise.
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Question 3 - Solution Uniform charge delivery minimizes resistive loss over a fixed time t I (a) Method and calculation ∫T 0 I2dt −2(Q/T) ∫T 0 I dt + Q2/T ≥0. W = R ∫T 0 I2dt ≥RQ2/T, Ioptimal = Q/T. (b) Interpretation and further calculation Ip = Q/(fT), Wp = RI2 pfT = RQ2/(fT). Wp/Wmin = 1/f ≥1. Physical check Equality requires constant current almost everywhere; concentrating transfer raises resistive loss.

Question 3

Uniform charge delivery minimizes resistive loss over a fixed time

A nonnegative current waveform transports prescribed charge Q through constant resistance R during time T. No other constraint is imposed.

Diagram shown in the original SVG worksheet.

  1. Use ∫0T[I(t)−Q/T]2dt≥0\int_0^T[I(t)-Q/T]^2dt\ge0 to derive the least possible heating.

  2. Compare with delivery by a constant pulse lasting only fraction f of T, with zero current otherwise.

Question 3 - Solution

Uniform charge delivery minimizes resistive loss over a fixed time

Diagram shown in the original SVG worksheet.

(a) Method and calculation

∫0TI2dt−2(Q/T)∫0TIdt+Q2/T≥0.\int_0^T I^2dt-2(Q/T)\int_0^T I\,dt+Q^2/T\ge0.W=R∫0TI2dt≥RQ2/T,Ioptimal=Q/T.W=R\int_0^T I^2dt\ge RQ^2/T,\quad I_{\mathrm{optimal}}=Q/T.

(b) Interpretation and further calculation

Ip=Q/(fT),Wp=RIp2fT=RQ2/(fT).I_p=Q/(fT),\quad W_p=RI_p^2fT=RQ^2/(fT).Wp/Wmin=1/f≥1.W_p/W_{\min}=1/f\ge1.

Physical check

Equality requires constant current almost everywhere; concentrating transfer raises resistive loss.