Ohm's Law — Question 2

Section 26-4 · Physics pages 4214–4215

Question 2 A cubic voltage law has distinct static and incremental resistance A symmetric device at fixed temperature obeys V (I) = R0I + γI3, with R0, γ > 0. I V Axes and labels specify the model; the sketch is schematic. (a) Find static resistance V/I and differential resistance dV/dI at I = Ib̸ = 0. (b) Find the first-order current change from a small voltage perturbation and quantify the error from using static resistance.
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Question 2 - Solution A cubic voltage law has distinct static and incremental resistance I V (a) Method and calculation Rs = V/I = R0 + γI2 b . rd = dV/dI = R0 + 3γI2 b . (b) Interpretation and further calculation δI ≃δV/rd = δV R0 + 3γI2 b . δIRs δIrd = R0 + 3γI2 b R0 + γI2 b > 1. Physical check Incremental response is governed by a tangent; a full operating ratio is a secant.

Question 2

A cubic voltage law has distinct static and incremental resistance

A symmetric device at fixed temperature obeys V(I)=R0I+γI3V(I)=R_0I+\gamma I^3, with R0,γ>0R_0,\gamma>0.

Diagram shown in the original SVG worksheet.

  1. Find static resistance V/I and differential resistance dV/dI at I=Ib≠0I=I_b\ne0.

  2. Find the first-order current change from a small voltage perturbation and quantify the error from using static resistance.

Question 2 - Solution

A cubic voltage law has distinct static and incremental resistance

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Rs=V/I=R0+γIb2.R_s=V/I=R_0+\gamma I_b^2.rd=dV/dI=R0+3γIb2.r_d=dV/dI=R_0+3\gamma I_b^2.

(b) Interpretation and further calculation

δI≃δV/rd=δVR0+3γIb2.\delta I\simeq\delta V/r_d=\frac{\delta V}{R_0+3\gamma I_b^2}.δIRsδIrd=R0+3γIb2R0+γIb2>1.\frac{\delta I_{R_s}}{\delta I_{r_d}}=\frac{R_0+3\gamma I_b^2}{R_0+\gamma I_b^2}>1.

Physical check

Incremental response is governed by a tangent; a full operating ratio is a secant.