Resistance and Resistivity — Question 8

Section 26-3 · Physics pages 4206–4207

Question 8 A layered conductor has different effective resistivities along and across layers Two materials occupy equal thicknesses in a laminated block. Their resistivities are ρ1 = ρ and ρ2 = 4ρ. Ignore interface resistance. Compare current perpendicular and parallel to layers. ρ 4ρ Schematic; labels, not drawing lengths, specify the data. (a) Find the effective resistivity for perpendicular flow using equal normal current density. (b) Find it for parallel flow using equal tangential electric field, and compare the two.
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Question 8 - Solution A layered conductor has different effective resistivities along and across layers ρ 4ρ (a) Method and calculation Eavg = 1 2(ρ1J + ρ2J). ρ⊥= (ρ1 + ρ2)/2 = 5ρ/2. (b) Interpretation and further calculation Javg = 1 2(E/ρ1 + E/ρ2) = 5E/(8ρ). ρ∥= 8ρ/5, ρ⊥/ρ∥= 25/16. Physical check Structural anisotropy can arise from layers of individually isotropic materials.

Question 8

A layered conductor has different effective resistivities along and across layers

Two materials occupy equal thicknesses in a laminated block. Their resistivities are ρ1=ρ\rho_1=\rho and ρ2=4ρ\rho_2=4\rho. Ignore interface resistance. Compare current perpendicular and parallel to layers.

Diagram shown in the original SVG worksheet.

  1. Find the effective resistivity for perpendicular flow using equal normal current density.

  2. Find it for parallel flow using equal tangential electric field, and compare the two.

Question 8 - Solution

A layered conductor has different effective resistivities along and across layers

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Eavg=12(ρ1J+ρ2J).E_{\mathrm{avg}}=\tfrac12(\rho_1J+\rho_2J).ρ⟂=(ρ1+ρ2)/2=5ρ/2.\rho_\perp=(\rho_1+\rho_2)/2=5\rho/2.

(b) Interpretation and further calculation

Javg=12(E/ρ1+E/ρ2)=5E/(8ρ).J_{\mathrm{avg}}=\tfrac12(E/\rho_1+E/\rho_2)=5E/(8\rho).ρ∥=8ρ/5,ρ⟂/ρ∥=25/16.\rho_\parallel=8\rho/5,\quad\rho_\perp/\rho_\parallel=25/16.

Physical check

Structural anisotropy can arise from layers of individually isotropic materials.