Resistance and Resistivity — Question 5

Section 26-3 · Physics pages 4200–4201

Question 5 Orthogonal measurements separate a material property from specimen shape A homogeneous isotropic block has dimensions Lx = 4.0 cm, Ly = 2.0 cm and Lz = 1.0 cm. Ideal full-face electrodes measure Rx = 8.0 mΩalong x. Lx Ly Lz Schematic; labels, not drawing lengths, specify the data. (a) Infer resistivity and predict resistance along y. (b) Find the ratio Rx/Rz and explain why these unequal resistances do not imply anisotropy.
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Question 5 - Solution Orthogonal measurements separate a material property from specimen shape Lx Ly Lz (a) Method and calculation ρ = RxLyLz/Lx = 4.00 × 10−5 Ωm. Ry = ρLy/(LxLz) = 2.00 mΩ. (b) Interpretation and further calculation Rz = ρLz/(LxLy) = .500 mΩ. Rx/Rz = (Lx/Lz)2 = 16.0. Physical check Resistivity is direction-independent in this model; electrode separation and face area are not.

Question 5

Orthogonal measurements separate a material property from specimen shape

A homogeneous isotropic block has dimensions Lx=4.0L_x=4.0 cm, Ly=2.0L_y=2.0 cm and Lz=1.0L_z=1.0 cm. Ideal full-face electrodes measure Rx=8.0R_x=8.0 mΩ\Omega along x.

Diagram shown in the original SVG worksheet.

  1. Infer resistivity and predict resistance along y.

  2. Find the ratio Rx/RzR_x/R_z and explain why these unequal resistances do not imply anisotropy.

Question 5 - Solution

Orthogonal measurements separate a material property from specimen shape

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ρ=RxLyLz/Lx=4.00×10−5Ωm.\rho=R_xL_yL_z/L_x=4.00\times10^{-5}\,\Omega\,\mathrm m.Ry=ρLy/(LxLz)=2.00mΩ.R_y=\rho L_y/(L_xL_z)=2.00\,\mathrm{m\Omega}.

(b) Interpretation and further calculation

Rz=ρLz/(LxLy)=.500mΩ.R_z=\rho L_z/(L_xL_y)=.500\,\mathrm{m\Omega}.Rx/Rz=(Lx/Lz)2=16.0.R_x/R_z=(L_x/L_z)^2=16.0.

Physical check

Resistivity is direction-independent in this model; electrode separation and face area are not.