Dielectrics: An Atomic View — Question 1

Section 25-6 · Physics pages 4112–4113

Question 1 A harmonic atomic model produces an induced dipole proportional to the field A fixed charge +e is at x=0. Its bound negative charge -e is displaced by x and experiences restoring force -Kx in a uniform field Eˆx. Let K>0. −e +e E p Schematic; labels, not drawing lengths, specify the data. (a) Find the equilibrium displacement and dipole moment. (b) Include elastic and electric terms in the energy and find its minimized value; compare with inserting the final induced moment into -pE alone.
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Question 1 - Solution A harmonic atomic model produces an induced dipole proportional to the field −e +e E p (a) Method and calculation −Kx −eE = 0 ⇒x∗= −eE/K. p = −ex∗= e2E/K = αE, α = e2/K. (b) Interpretation and further calculation U(x) = 1 2Kx2 + eEx ⇒U(x∗) = −e2E2 2K = −1 2αE2. −pE = −αE2 omits the positive elastic energy required to create the dipole. Physical check The negative charge moves against the field, but the induced dipole moment points with the field.

Question 1

A harmonic atomic model produces an induced dipole proportional to the field

A fixed charge +e is at x=0. Its bound negative charge -e is displaced by x and experiences restoring force -Kx in a uniform field E𝒙̂E\hat{\mathbf x}. Let K>0.

Diagram shown in the original SVG worksheet.

  1. Find the equilibrium displacement and dipole moment.

  2. Include elastic and electric terms in the energy and find its minimized value; compare with inserting the final induced moment into -pE alone.

Question 1 - Solution

A harmonic atomic model produces an induced dipole proportional to the field

Diagram shown in the original SVG worksheet.

(a) Method and calculation

−Kx−eE=0⇒x*=−eE/K.-Kx-eE=0\Rightarrow x_*=-eE/K.p=−ex*=e2E/K=αE,α=e2/K.p=-ex_*=e^2E/K=\alpha E,\quad\alpha=e^2/K.

(b) Interpretation and further calculation

U(x)=12Kx2+eEx⇒U(x*)=−e2E22K=−12αE2.U(x)=\tfrac12Kx^2+eEx\Rightarrow U(x_*)=-\frac{e^2E^2}{2K}=-\tfrac12\alpha E^2.−pE=−αE2-pE=-\alpha E^2omits the positive elastic energy required to create the dipole.

Physical check

The negative charge moves against the field, but the induced dipole moment points with the field.