Capacitors in Parallel and in Series — Question 1

Section 25-3 · Physics pages 4052–4053

Question 1 Parallel branches share voltage while their terminal charges add Ideal capacitors C1=3.00 nF and C2=6.00 nF are connected in parallel across 12.0 V, starting uncharged. A B C1 C2 Schematic; labels, not drawing lengths, specify the data. (a) Derive and calculate the equivalent capacitance and branch charges. (b) If C2 is disconnected while C1 remains attached to the source, find the retained charge on each isolated or connected capacitor, neglecting switch capacitance.
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Question 1 - Solution Parallel branches share voltage while their terminal charges add A B C1 C2 (a) Method and calculation Qtotal = C1V + C2V ⇒Ceq = C1 + C2 = 9.00 nF. Q1 = 36.0 nC, Q2 = 72.0 nC, Qtotal = 108 nC. (b) Interpretation and further calculation Q1,f = C1V = 36.0 nC. Q2,f = Q2,i = 72.0 nC, V2,f = Q2,f/C2 = 12.0 V. Physical check Disconnection alone does not discharge an ideal capacitor; charge remains on its separated terminals.

Question 1

Parallel branches share voltage while their terminal charges add

Ideal capacitors C1=3.00 nF and C2=6.00 nF are connected in parallel across 12.0 V, starting uncharged.

Diagram shown in the original SVG worksheet.

  1. Derive and calculate the equivalent capacitance and branch charges.

  2. If C2 is disconnected while C1 remains attached to the source, find the retained charge on each isolated or connected capacitor, neglecting switch capacitance.

Question 1 - Solution

Parallel branches share voltage while their terminal charges add

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Qtotal=C1V+C2V⇒Ceq=C1+C2=9.00nF.Q_{\mathrm{total}}=C_1V+C_2V\Rightarrow C_{\mathrm{eq}}=C_1+C_2=9.00\,\mathrm{nF}.Q1=36.0nC,Q2=72.0nC,Qtotal=108nC.Q_1=36.0\,\mathrm{nC},\quad Q_2=72.0\,\mathrm{nC},\quad Q_{\mathrm{total}}=108\,\mathrm{nC}.

(b) Interpretation and further calculation

Q1,f=C1V=36.0nC.Q_{1,f}=C_1V=36.0\,\mathrm{nC}.Q2,f=Q2,i=72.0nC,V2,f=Q2,f/C2=12.0V.Q_{2,f}=Q_{2,i}=72.0\,\mathrm{nC},\quad V_{2,f}=Q_{2,f}/C_2=12.0\,\mathrm V.

Physical check

Disconnection alone does not discharge an ideal capacitor; charge remains on its separated terminals.