Calculating the Field from the Potential — Question 7

Section 24-9 · Physics pages 3964–3965

Question 7 A piecewise continuous potential determines the sign of a surface charge Near the plane x=0, V = V0 + ax for x<0 and V = V0 + bx for x>0. The medium is vacuum and the only singular source is a surface charge at the plane. x V Schematic; labels, not drawing lengths, specify the data. (a) Find the one-sided fields and the surface charge density using Ex(0+) −Ex(0−) = σ/ϵ0. (b) For a=300 V/m and b=-100 V/m find σ/ϵ0 and the electric force on a test charge away from the sheet on each side.
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Question 7 - Solution A piecewise continuous potential determines the sign of a surface charge x V (a) Method and calculation Ex(0−) = −a, Ex(0+) = −b. σ = ϵ0(a −b). (b) Interpretation and further calculation σ/ϵ0 = 400 V/m > 0. F = qE = { −300qˆx V/m x < 0, +100qˆx V/m x > 0. Physical check Potential remains continuous; the slope jump carries the surface-charge information. The ideal sheet value itself requires a separate force convention.

Question 7

A piecewise continuous potential determines the sign of a surface charge

Near the plane x=0, V=V0+axV=V_0+a x for x<0 and V=V0+bxV=V_0+b x for x>0. The medium is vacuum and the only singular source is a surface charge at the plane.

Diagram shown in the original SVG worksheet.

  1. Find the one-sided fields and the surface charge density using Ex(0+)−Ex(0−)=σ/ϵ0E_x(0^+)-E_x(0^-)=\sigma/\epsilon_0.

  2. For a=300 V/m and b=-100 V/m find σ/ϵ0\sigma/\epsilon_0 and the electric force on a test charge away from the sheet on each side.

Question 7 - Solution

A piecewise continuous potential determines the sign of a surface charge

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Ex(0−)=−a,Ex(0+)=−b.E_x(0^-)=-a,\quad E_x(0^+)=-b.σ=ϵ0(a−b).\sigma=\epsilon_0(a-b).

(b) Interpretation and further calculation

σ/ϵ0=400V/m>0.\sigma/\epsilon_0=400\,\mathrm{V/m}>0.𝑭=q𝑬={−300q𝒙̂V/mx<0,+100q𝒙̂V/mx>0.\mathbf F=q\mathbf E=\begin{cases}-300q\hat{\mathbf x}\,\mathrm{V/m}&x<0,\\+100q\hat{\mathbf x}\,\mathrm{V/m}&x>0.\end{cases}

Physical check

Potential remains continuous; the slope jump carries the surface-charge information. The ideal sheet value itself requires a separate force convention.