Potential Due to a Continuous Charge Distribution — Question 10

Section 24-8 · Physics pages 3950–3951

Question 10 A radially graded disk changes potential even when its total charge is fixed A disk of radius R has σ(s) = Cs with C>0. Compare it with a uniform disk of the same total charge Q and radius R. Use infinity reference. z R P Schematic; labels, not drawing lengths, specify the data. (a) Normalize C in terms of Q and find the graded disk center potential. (b) Find the ratio to the uniform disk center potential and explain the direction of the change through the radial weighting.
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Question 10 - Solution A radially graded disk changes potential even when its total charge is fixed z R P (a) Method and calculation Q = 2πC ∫R 0 s2ds = 2πCR3 3 ⇒C = 3Q 2πR3 . Vgraded(0) = k ∫R 0 2πCs2ds s = πkCR2 = 3kQ 2R . (b) Interpretation and further calculation Vuniform(0) = 2πk Q πR2 R = 2kQ R . Vgraded(0)/Vuniform(0) = 3/4. Physical check The graded disk weights outer radii more strongly; at the center those charges contribute less voltage per unit charge.

Question 10

A radially graded disk changes potential even when its total charge is fixed

A disk of radius R has σ(s)=Cs\sigma(s)=Cs with C>0. Compare it with a uniform disk of the same total charge Q and radius R. Use infinity reference.

Diagram shown in the original SVG worksheet.

  1. Normalize C in terms of Q and find the graded disk center potential.

  2. Find the ratio to the uniform disk center potential and explain the direction of the change through the radial weighting.

Question 10 - Solution

A radially graded disk changes potential even when its total charge is fixed

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Q=2πC∫0Rs2ds=2πCR33⇒C=3Q2πR3.Q=2\pi C\int_0^R s^2ds=\frac{2\pi CR^3}{3}\Rightarrow C=\frac{3Q}{2\pi R^3}.Vgraded(0)=k∫0R2πCs2dss=πkCR2=3kQ2R.V_{\mathrm{graded}}(0)=k\int_0^R\frac{2\pi Cs^2ds}{s}=\pi kCR^2=\frac{3kQ}{2R}.

(b) Interpretation and further calculation

Vuniform(0)=2πkQπR2R=2kQR.V_{\mathrm{uniform}}(0)=2\pi k\frac{Q}{\pi R^2}R=\frac{2kQ}{R}.Vgraded(0)/Vuniform(0)=3/4.V_{\mathrm{graded}}(0)/V_{\mathrm{uniform}}(0)=3/4.

Physical check

The graded disk weights outer radii more strongly; at the center those charges contribute less voltage per unit charge.