Potential Due to a Continuous Charge Distribution — Question 6

Section 24-8 · Physics pages 3942–3943

Question 6 Removing a central disk changes the center voltage and axial curvature A uniformly charged annulus has inner radius a, outer radius b>a and surface density σ > 0. Set zero potential at infinity. z b a Schematic; labels, not drawing lengths, specify the data. (a) Find the potential along its symmetry axis by subtracting two disk potentials. (b) Find V(0) and its expansion through z squared near the center; classify the axial extremum.
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Question 6 - Solution Removing a central disk changes the center voltage and axial curvature z b a (a) Method and calculation V (z) = 2πkσ (√ b2 + z2 − √ a2 + z2 ) . V (0) = 2πkσ(b −a). (b) Interpretation and further calculation V (z) = 2πkσ [ (b −a) + z2 2 (1 b −1 a ) + O(z4) ] . V ′′(0) = 2πkσ(1/b −1/a) < 0, so the center is an axial maximum. Physical check The result describes stability along the axis only; it does not establish a three-dimensional equilibrium classification.

Question 6

Removing a central disk changes the center voltage and axial curvature

A uniformly charged annulus has inner radius a, outer radius b>a and surface density σ>0\sigma>0. Set zero potential at infinity.

Diagram shown in the original SVG worksheet.

  1. Find the potential along its symmetry axis by subtracting two disk potentials.

  2. Find V(0) and its expansion through z squared near the center; classify the axial extremum.

Question 6 - Solution

Removing a central disk changes the center voltage and axial curvature

Diagram shown in the original SVG worksheet.

(a) Method and calculation

V(z)=2πkσ(b2+z2−a2+z2).V(z)=2\pi k\sigma\left(\sqrt{b^2+z^2}-\sqrt{a^2+z^2}\right).V(0)=2πkσ(b−a).V(0)=2\pi k\sigma(b-a).

(b) Interpretation and further calculation

V(z)=2πkσ[(b−a)+z22(1b−1a)+O(z4)].V(z)=2\pi k\sigma\left[(b-a)+\frac{z^2}{2}\left(\frac1b-\frac1a\right)+O(z^4)\right].V′′(0)=2πkσ(1/b−1/a)<0,V\prime\prime(0)=2\pi k\sigma(1/b-1/a)<0,so the center is an axial maximum.

Physical check

The result describes stability along the axis only; it does not establish a three-dimensional equilibrium classification.