Potential Due to an Electric Dipole — Question 10

Section 24-7 · Physics pages 3930–3931

Question 10 Opposite-angle voltage differences isolate an ideal dipole contribution A remote source has the model potential V (r, θ) = kQ/r + kp cos θ/r2 + C. The axis is known, but Q,p and the constant offset C are unknown. At fixed R measure V (0) = 14 V, V (π) = 6 V and V (π/2) = 10 V. p 10 V 14 V 6 V Schematic; labels, not drawing lengths, specify the data. (a) Find kp/R2 and check the angular consistency of the model. (b) An additional equatorial reading at radius 2R is 7 V. Find kQ/R and C.
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Question 10 - Solution Opposite-angle voltage differences isolate an ideal dipole contribution p 10 V 14 V 6 V (a) Method and calculation V (0) −V (π) = 2kp/R2 ⇒kp/R2 = 4 V. 1 2[V (0) + V (π)] = 10 V = V (π/2). (b) Interpretation and further calculation A + C = 10, A/2 + C = 7, A ≡kQ/R. A = 6 V, C = 4 V. Physical check Angular differences remove both the monopole voltage and a common reference offset; a second radius separates those two remaining terms.

Question 10

Opposite-angle voltage differences isolate an ideal dipole contribution

A remote source has the model potential V(r,θ)=kQ/r+kpcos⁡θ/r2+CV(r,\theta)=kQ/r+kp\cos\theta/r^2+C. The axis is known, but Q,p and the constant offset C are unknown. At fixed R measure V(0)=14V(0)=14 V, V(π)=6V(\pi)=6 V and V(π/2)=10V(\pi/2)=10 V.

Diagram shown in the original SVG worksheet.

  1. Find kp/R2kp/R^2 and check the angular consistency of the model.

  2. An additional equatorial reading at radius 2R is 7 V. Find kQ/RkQ/R and C.

Question 10 - Solution

Opposite-angle voltage differences isolate an ideal dipole contribution

Diagram shown in the original SVG worksheet.

(a) Method and calculation

V(0)−V(π)=2kp/R2⇒kp/R2=4V.V(0)-V(\pi)=2kp/R^2\Rightarrow kp/R^2=4\,\mathrm V.12[V(0)+V(π)]=10V=V(π/2).\tfrac12[V(0)+V(\pi)]=10\,\mathrm V=V(\pi/2).

(b) Interpretation and further calculation

A+C=10,A/2+C=7,A≡kQ/R.A+C=10,\quad A/2+C=7,\quad A\equiv kQ/R.A=6V,C=4V.A=6\,\mathrm V,\quad C=4\,\mathrm V.

Physical check

Angular differences remove both the monopole voltage and a common reference offset; a second radius separates those two remaining terms.