Potential Due to a Group of Point Charges — Question 3

Section 24-6 · Physics pages 3896–3897

Question 3 A zero-potential locus of unequal opposite charges is a sphere Charges +Q at the origin and −2Q at (d, 0, 0) have Q,d>0. Use the infinity reference. +Q −2Q x Schematic; labels, not drawing lengths, specify the data. (a) Derive the full three-dimensional V=0 surface. (b) Find its center, radius and axial intersections, and identify which source it surrounds.
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Question 3 - Solution A zero-potential locus of unequal opposite charges is a sphere +Q −2Q x (a) Method and calculation r−= 2r+, (x −d)2 + y2 + z2 = 4(x2 + y2 + z2). ( x + d 3 )2 + y2 + z2 = (2d 3 )2 . (b) Interpretation and further calculation rc = −d 3 ˆx, Rs = 2d/3, xends = −d, d/3. |0 −xc| = d/3 < Rs, |d −xc| = 4d/3 > Rs. The sphere encloses the smaller positive source. Physical check The sphere is a voltage level, not a conducting shell; its existence does not alter either source.

Question 3

A zero-potential locus of unequal opposite charges is a sphere

Charges +Q at the origin and −2Q-2Q at (d,0,0)(d,0,0) have Q,d>0. Use the infinity reference.

Diagram shown in the original SVG worksheet.

  1. Derive the full three-dimensional V=0 surface.

  2. Find its center, radius and axial intersections, and identify which source it surrounds.

Question 3 - Solution

A zero-potential locus of unequal opposite charges is a sphere

Diagram shown in the original SVG worksheet.

(a) Method and calculation

r−=2r+,(x−d)2+y2+z2=4(x2+y2+z2).r_- =2r_+,\quad (x-d)^2+y^2+z^2=4(x^2+y^2+z^2).(x+d3)2+y2+z2=(2d3)2.\left(x+\frac d3\right)^2+y^2+z^2=\left(\frac{2d}{3}\right)^2.

(b) Interpretation and further calculation

𝒓c=−d3𝒙̂,Rs=2d/3,xends=−d,d/3.\mathbf r_c=-\frac d3\hat{\mathbf x},\quad R_s=2d/3,\quad x_{\mathrm{ends}}=-d,d/3.|0−xc|=d/3<Rs,|d−xc|=4d/3>Rs.|0-x_c|=d/3<R_s,\quad|d-x_c|=4d/3>R_s.The sphere encloses the smaller positive source.

Physical check

The sphere is a voltage level, not a conducting shell; its existence does not alter either source.