Potential Due to a Point Charge — Question 9

Section 24-5 · Physics pages 3888–3889

Question 9 A circular Coulomb orbit partitions kinetic and potential energy A particle of charge −q and mass m moves in a circular orbit of radius R about fixed +Q, with q,Q positive. Ignore radiation and use nonrelativistic mechanics. +Q −q Schematic; labels, not drawing lengths, specify the data. (a) Use centripetal balance to find speed and kinetic energy. (b) Find total mechanical energy and the additional energy required to reach infinity with zero final speed.
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Question 9 - Solution A circular Coulomb orbit partitions kinetic and potential energy +Q −q (a) Method and calculation mv2 R = kQq R2 ⇒v = √ kQq mR . K = kQq 2R , U = −kQq R . (b) Interpretation and further calculation E = K + U = −kQq 2R . ∆Eescape = 0 −E = kQq 2R . Physical check Escape energy from an orbit is half the magnitude of the interaction energy because the particle already has kinetic energy.

Question 9

A circular Coulomb orbit partitions kinetic and potential energy

A particle of charge −q-q and mass m moves in a circular orbit of radius R about fixed +Q+Q, with q,Q positive. Ignore radiation and use nonrelativistic mechanics.

Diagram shown in the original SVG worksheet.

  1. Use centripetal balance to find speed and kinetic energy.

  2. Find total mechanical energy and the additional energy required to reach infinity with zero final speed.

Question 9 - Solution

A circular Coulomb orbit partitions kinetic and potential energy

Diagram shown in the original SVG worksheet.

(a) Method and calculation

mv2R=kQqR2⇒v=kQqmR.\frac{mv^2}{R}=\frac{kQq}{R^2}\Rightarrow v=\sqrt{\frac{kQq}{mR}}.K=kQq2R,U=−kQqR.K=\frac{kQq}{2R},\quad U=-\frac{kQq}{R}.

(b) Interpretation and further calculation

ℰ=K+U=−kQq2R.\mathcal E=K+U=-\frac{kQq}{2R}.Δℰescape=0−ℰ=kQq2R.\Delta\mathcal E_{\mathrm{escape}}=0-\mathcal E=\frac{kQq}{2R}.

Physical check

Escape energy from an orbit is half the magnitude of the interaction energy because the particle already has kinetic energy.