Potential Due to a Point Charge — Question 2

Section 24-5 · Physics pages 3874–3875

Question 2 Potential and field together locate an unseen point source Use k = 8.99 × 109 N m2/C2. At P, a single point charge produces V=180 V and field magnitude E=600 V/m. The potential zero is at infinity. Q P east Schematic; labels, not drawing lengths, specify the data. (a) Find the distance from P to the source and the source charge. (b) If the measured field at P points east, locate the source relative to P; explain why a voltage offset would spoil the distance inference.
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Question 2 - Solution Potential and field together locate an unseen point source Q P east (a) Method and calculation V = kQ/r, E = k|Q|/r2 ⇒r = |V |/E = .300 m. Q = V r/k = 6.00667 nC > 0. (b) Interpretation and further calculation E points away from Q > 0 ⇒Q lies .300 m west of P. Vmeasured = kQ/r + C ⇒|Vmeasured|/E̸ = r in general. Physical check The inversion uses both the single-source model and its infinity reference.

Question 2

Potential and field together locate an unseen point source

Use k=8.99×109Nm2/C2k=8.99\times10^9\,\mathrm{N\,m^2/C^2}. At P, a single point charge produces V=180 V and field magnitude E=600 V/m. The potential zero is at infinity.

Diagram shown in the original SVG worksheet.

  1. Find the distance from P to the source and the source charge.

  2. If the measured field at P points east, locate the source relative to P; explain why a voltage offset would spoil the distance inference.

Question 2 - Solution

Potential and field together locate an unseen point source

Diagram shown in the original SVG worksheet.

(a) Method and calculation

V=kQ/r,E=k|Q|/r2⇒r=|V|/E=.300m.V=kQ/r,\quad E=k|Q|/r^2\Rightarrow r=|V|/E=.300\,\mathrm m.Q=Vr/k=6.00667nC>0.Q=Vr/k=6.00667\,\mathrm{nC}>0.

(b) Interpretation and further calculation

𝑬 points away from Q>0⇒Q lies .300m west of P.\mathbf E\text{ points away from }Q>0\Rightarrow Q\text{ lies }.300\,\mathrm m\text{ west of P}.Vmeasured=kQ/r+C⇒|Vmeasured|/E≠rin general.V_{\mathrm{measured}}=kQ/r+C\Rightarrow |V_{\mathrm{measured}}|/E\ne r\quad\text{in general}.

Physical check

The inversion uses both the single-source model and its infinity reference.