Calculating the Potential from the Field — Question 4

Section 24-4 · Physics pages 3858–3859

Question 4 A radial power law admits an infinity reference only for sufficiently fast decay A radial field outside r=a is E = Cr−nˆr with C positive and n real. a Schematic; labels, not drawing lengths, specify the data. (a) Determine for which n the convention V(infinity)=0 is possible and derive V(r) in that case. (b) For n=1 use V(a)=0 instead; find V(r) and the voltage from a to 3a.
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Question 4 - Solution A radial power law admits an infinity reference only for sufficiently fast decay a (a) Method and calculation V (r) = ∫∞ r Cu−n du. n > 1 : V (r) = C n −1r1−n; n ≤1 : integral diverges. (b) Interpretation and further calculation n = 1 : V (r) −V (a) = − ∫r a C u du = −C ln(r/a). V (3a) −V (a) = −C ln 3. Physical check Finite voltage differences can exist even when choosing zero potential at infinity is mathematically impossible.

Question 4

A radial power law admits an infinity reference only for sufficiently fast decay

A radial field outside r=a is 𝑬=Cr−n𝒓̂\mathbf E=C r^{-n}\hat{\mathbf r} with C positive and n real.

Diagram shown in the original SVG worksheet.

  1. Determine for which n the convention V(infinity)=0 is possible and derive V(r) in that case.

  2. For n=1 use V(a)=0 instead; find V(r) and the voltage from a to 3a.

Question 4 - Solution

A radial power law admits an infinity reference only for sufficiently fast decay

Diagram shown in the original SVG worksheet.

(a) Method and calculation

V(r)=∫r∞Cu−ndu.V(r)=\int_r^\infty C u^{-n}\,du.n>1:V(r)=Cn−1r1−n;n≤1:integral diverges.n>1:\quad V(r)=\frac{C}{n-1}r^{1-n};\qquad n\le1:\ \text{integral diverges}.

(b) Interpretation and further calculation

n=1:V(r)−V(a)=−∫arCudu=−Cln⁡(r/a).n=1:\quad V(r)-V(a)=-\int_a^r\frac C u\,du=-C\ln(r/a).V(3a)−V(a)=−Cln⁡3.V(3a)-V(a)=-C\ln3.

Physical check

Finite voltage differences can exist even when choosing zero potential at infinity is mathematically impossible.