Electric Potential Energy — Question 10

Section 24-1 · Physics pages 3810–3811

Question 10 A time-dependent prescribed field requires an explicit energy-source term A one-dimensional prescribed field is E(t), spatially uniform. Assign a charge q the energy U(x, t) = −qE(t)x. Assume the electric force dominates and use Fx = −∂U/∂x. t E(t) Axes and labels specify the model; the sketch is schematic. (a) Derive the rate of change of K+U for a freely moving particle. (b) Now hold the particle at fixed x = x0 while E(t) = Ei + αt changes for duration T. Find its assigned energy change and electric mechanical work.
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Question 10 - Solution A time-dependent prescribed field requires an explicit energy-source term t E(t) (a) Method and calculation dK dt = qE(t) ˙x, dU dt = −qE(t) ˙x −q ˙E(t)x. d(K + U) dt = −q ˙E(t)x = ∂U ∂t . (b) Interpretation and further calculation x = x0 : ∆U = −qαTx0. We = ∫ qE(t) dx = 0. The assigned particle-plus-interaction energy changes because the external source varies the field; time independence was essential to the earlier conservation rule. Physical check The energy zero is fixed by the supplied U; adding an arbitrary function of time would change its bookkeeping rate but not the force.

Question 10

A time-dependent prescribed field requires an explicit energy-source term

A one-dimensional prescribed field is E(t)E(t), spatially uniform. Assign a charge q the energy U(x,t)=−qE(t)xU(x,t)=-qE(t)x. Assume the electric force dominates and use Fx=−∂U/∂xF_x=-\partial U/\partial x.

Diagram shown in the original SVG worksheet.

  1. Derive the rate of change of K+U for a freely moving particle.

  2. Now hold the particle at fixed x=x0x=x_0 while E(t)=Ei+αtE(t)=E_i+\alpha t changes for duration T. Find its assigned energy change and electric mechanical work.

Question 10 - Solution

A time-dependent prescribed field requires an explicit energy-source term

Diagram shown in the original SVG worksheet.

(a) Method and calculation

dKdt=qE(t)ẋ,dUdt=−qE(t)ẋ−qĖ(t)x.\frac{dK}{dt}=qE(t)\dot x,\quad\frac{dU}{dt}=-qE(t)\dot x-q\dot E(t)x.d(K+U)dt=−qĖ(t)x=∂U∂t.\frac{d(K+U)}{dt}=-q\dot E(t)x=\frac{\partial U}{\partial t}.

(b) Interpretation and further calculation

x=x0:ΔU=−qαTx0.x=x_0:\quad\Delta U=-q\alpha Tx_0.We=∫qE(t)dx=0.W_e=\int qE(t)\,dx=0.The assigned particle-plus-interaction energy changes because the external source varies the field; time independence was essential to the earlier conservation rule.

Physical check

The energy zero is fixed by the supplied U; adding an arbitrary function of time would change its bookkeeping rate but not the force.