Applying Gauss' Law: Cylindrical Symmetry — Question 7

Section 23-6 · Physics pages 3744–3745

Question 7 An annular field profile determines bulk density and an unresolved core charge In an infinite cylindrically symmetric system, the measured radial field is Er(r) = Ar + B/r only in the annulus a < r < b. A and B are constants. Nothing is specified about the charge profile in r < a. core a b Cross-section perpendicular to an infinite cylinder axis; end effects are excluded. (a) Infer the volume density throughout the measured annulus. (b) Find the total charge per length in the unresolved core. Explain why B alone cannot automatically be identified with an actual line charge on the axis.
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Question 7 - Solution An annular field profile determines bulk density and an unresolved core charge core a b (a) Method and calculation λenc(r) = 2πϵ0rEr = 2πϵ0(Ar2 + B). 2πrρ(r) = dλenc dr = 4πϵ0Ar ⇒ρ = 2ϵ0A. (b) Interpretation and further calculation λcore = λenc(a+) = 2πϵ0(Aa2 + B). λenc(r) = λcore + πρ(r2 −a2). Only with extra information extending the same uniform bulk density toward the axis could 2πϵ0B be assigned to an additional singular line source. Physical check A field measured on an annulus constrains enclosed totals but does not resolve the internal spatial arrangement of core charge.

Question 7

An annular field profile determines bulk density and an unresolved core charge

In an infinite cylindrically symmetric system, the measured radial field is Er(r)=Ar+B/rE_r(r)=Ar+B/r only in the annulus a<r<ba<r<b. A and B are constants. Nothing is specified about the charge profile in r<ar<a.

Diagram shown in the original SVG worksheet.

  1. Infer the volume density throughout the measured annulus.

  2. Find the total charge per length in the unresolved core. Explain why B alone cannot automatically be identified with an actual line charge on the axis.

Question 7 - Solution

An annular field profile determines bulk density and an unresolved core charge

Diagram shown in the original SVG worksheet.

(a) Method and calculation

λenc(r)=2πϵ0rEr=2πϵ0(Ar2+B).\lambda_{\mathrm{enc}}(r)=2\pi\epsilon_0rE_r=2\pi\epsilon_0(Ar^2+B).2πrρ(r)=dλencdr=4πϵ0Ar⇒ρ=2ϵ0A.2\pi r\rho(r)=\frac{d\lambda_{\mathrm{enc}}}{dr}=4\pi\epsilon_0Ar\Rightarrow\rho=2\epsilon_0A.

(b) Interpretation and further calculation

λcore=λenc(a+)=2πϵ0(Aa2+B).\lambda_{\mathrm{core}}=\lambda_{\mathrm{enc}}(a^+)=2\pi\epsilon_0(Aa^2+B).λenc(r)=λcore+πρ(r2−a2).\lambda_{\mathrm{enc}}(r)=\lambda_{\mathrm{core}}+\pi\rho(r^2-a^2).Only with extra information extending the same uniform bulk density toward the axis could 2πϵ0B2\pi\epsilon_0B be assigned to an additional singular line source.

Physical check

A field measured on an annulus constrains enclosed totals but does not resolve the internal spatial arrangement of core charge.