A Charged Isolated Conductor — Question 6

Section 23-5 · Physics pages 3722–3723

Question 6 A neutral collection inside a cavity can induce zero net wall charge and nonzero fields A closed cavity inside an isolated neutral conductor contains two fixed, separated charges +q and −q, neither touching the wall. The whole system is in electrostatic equilibrium. +q −q Cross-section of a conducting shell in electrostatic equilibrium; shaded material is metal. (a) Find the total induced charge on the cavity wall and the total outer-surface charge. (b) Explain why the zero cavity-wall charge total does not imply zero surface density everywhere or zero cavity field. Use a small Gaussian sphere enclosing only +q.
Show solutionHide solution
Question 6 - Solution A neutral collection inside a cavity can induce zero net wall charge and nonzero fields +q −q (a) Method and calculation Qcontents = q −q = 0, Qwall = −Qcontents = 0. Qouter = Qc −Qwall = 0. (b) Interpretation and further calculation Z wall σ dA = 0 does not require σ(P) = 0. I S+ E · dA = q/ϵ0̸ = 0. A field that vanished everywhere in the cavity could not satisfy the last equation. Local induced charges enforce zero field in the surrounding metal. Physical check A cavity containing separated charges is not an empty cavity, even when its net charge is zero.

Question 6

A neutral collection inside a cavity can induce zero net wall charge and nonzero fields

A closed cavity inside an isolated neutral conductor contains two fixed, separated charges +q+q and −q-q, neither touching the wall. The whole system is in electrostatic equilibrium.

Diagram shown in the original SVG worksheet.

  1. Find the total induced charge on the cavity wall and the total outer-surface charge.

  2. Explain why the zero cavity-wall charge total does not imply zero surface density everywhere or zero cavity field. Use a small Gaussian sphere enclosing only +q+q.

Question 6 - Solution

A neutral collection inside a cavity can induce zero net wall charge and nonzero fields

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Qcontents=q−q=0,Qwall=−Qcontents=0.Q_{\mathrm{contents}}=q-q=0,\quad Q_{\mathrm{wall}}=-Q_{\mathrm{contents}}=0.Qouter=Qc−Qwall=0.Q_{\mathrm{outer}}=Q_c-Q_{\mathrm{wall}}=0.

(b) Interpretation and further calculation

∫wallσdA=0does not requireσ(P)=0.\int_{\mathrm{wall}}\sigma\,dA=0\quad\text{does not require}\quad\sigma(P)=0.∮S+𝑬⋅d𝑨=q/ϵ0≠0.\oint_{S_+}\mathbf E\cdot d\mathbf A=q/\epsilon_0\ne0.A field that vanished everywhere in the cavity could not satisfy the last equation. Local induced charges enforce zero field in the surrounding metal.

Physical check

A cavity containing separated charges is not an empty cavity, even when its net charge is zero.