Gauss' Law — Question 4

Section 23-3 · Physics pages 3678–3679

Question 4 A missing face flux can be inferred with a hard uncertainty bound A closed six-face surface encloses exact charge Q = 60ϵ0 in SI units, so its total flux is 60 N m2/C. Five outward face fluxes are reported as 10, −20, 30, −40 and 50 N m2/C, each with an independent hard error bound of ±2 N m2/C. Q face 6 Schematic; labels, not drawing lengths, specify the data. (a) Find the nominal flux through the sixth face. (b) Find a guaranteed interval for that flux without assuming random errors. If the sixth face has area .500 m2, bound its average outward normal field.
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Question 4 - Solution A missing face flux can be inferred with a hard uncertainty bound Q face 6 (a) Method and calculation 5 X i=1 Φi = 10 −20 + 30 −40 + 50 = 30 N m2/C. Φ6 = Q/ϵ0 − 5 X i=1 Φi = 30 N m2/C. (b) Interpretation and further calculation δ 5 X i=1 Φi ≤ 5 X i=1 |δΦi| ≤10 ⇒20 ≤Φ6 ≤40. ⟨En⟩6 = Φ6/A6 ⇒40 ≤⟨En⟩6 ≤80 N/C. Quadrature of errors would not provide this guaranteed bound. Physical check The inferred mean normal field need not equal the field at the face center.

Question 4

A missing face flux can be inferred with a hard uncertainty bound

A closed six-face surface encloses exact charge Q=60ϵ0Q=60\epsilon_0 in SI units, so its total flux is 60 N m2^2/C. Five outward face fluxes are reported as 10, −20-20, 30, −40-40 and 50 N m2^2/C, each with an independent hard error bound of ±2\pm2 N m2^2/C.

Diagram shown in the original SVG worksheet.

  1. Find the nominal flux through the sixth face.

  2. Find a guaranteed interval for that flux without assuming random errors. If the sixth face has area .500.500 m2^2, bound its average outward normal field.

Question 4 - Solution

A missing face flux can be inferred with a hard uncertainty bound

Diagram shown in the original SVG worksheet.

(a) Method and calculation

∑i=15Φi=10−20+30−40+50=30Nm2/C.\sum_{i=1}^{5}\Phi_i=10-20+30-40+50=30\,\mathrm{N\,m^2/C}.Φ6=Q/ϵ0−∑i=15Φi=30Nm2/C.\Phi_6=Q/\epsilon_0-\sum_{i=1}^{5}\Phi_i=30\,\mathrm{N\,m^2/C}.

(b) Interpretation and further calculation

|δ∑i=15Φi|≤∑i=15|δΦi|≤10⇒20≤Φ6≤40.\left|\delta\sum_{i=1}^{5}\Phi_i\right|\le\sum_{i=1}^{5}|\delta\Phi_i|\le10\Rightarrow20\le\Phi_6\le40.⟨En⟩6=Φ6/A6⇒40≤⟨En⟩6≤80N/C.\langle E_n\rangle_6=\Phi_6/A_6\Rightarrow40\le\langle E_n\rangle_6\le80\,\mathrm{N/C}.Quadrature of errors would not provide this guaranteed bound.

Physical check

The inferred mean normal field need not equal the field at the face center.