A Dipole in an Electric Field — Question 9

Section 22-8 · Physics pages 3628–3629

Question 9 A dipole can follow a rotating field only below a torque threshold A uniform field of magnitude E rotates counterclockwise in a plane at constant rate ω > 0. A permanent dipole of magnitude p rotates about a fixed center with viscous resisting torque −b ˙θ, where b > 0. In the overdamped model inertia is neglected. Let δ = ωt −θ be the field lead angle. p E δ Schematic; labels, not drawing lengths, specify the data. (a) Derive the constant phase-lag condition and the maximum drive rate for synchronous rotation. (b) For bω/(pE) = 0.600, find the stable lag and dissipated power. Explain which of the two lag solutions is stable.
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Question 9 - Solution A dipole can follow a rotating field only below a torque threshold p E δ (a) Method and calculation b ˙θ = pE sin δ, ˙δ = ω −pE b sin δ. ˙δ = 0 ⇒sin δ = bω pE , ω ≤ωc = pE b . (b) Interpretation and further calculation δs = sin−1(.600) ≈36.8699◦, P = b ˙θ2 = bω2. δ = δs + η : ˙η ≃−pE b cos δs η. The branch with cos δs > 0 is stable; the supplementary branch is unstable. At the threshold the two branches meet and linear restoring relaxation vanishes. Physical check Although the angle between moment and field is constant in synchronous motion, the external field drive continually supplies dissipated mechanical energy.

Question 9

A dipole can follow a rotating field only below a torque threshold

A uniform field of magnitude E rotates counterclockwise in a plane at constant rate ω>0\omega>0. A permanent dipole of magnitude p rotates about a fixed center with viscous resisting torque −bθ̇-b\dot\theta, where b>0b>0. In the overdamped model inertia is neglected. Let δ=ωt−θ\delta=\omega t-\theta be the field lead angle.

Diagram shown in the original SVG worksheet.

  1. Derive the constant phase-lag condition and the maximum drive rate for synchronous rotation.

  2. For bω/(pE)=0.600b\omega/(pE)=0.600, find the stable lag and dissipated power. Explain which of the two lag solutions is stable.

Question 9 - Solution

A dipole can follow a rotating field only below a torque threshold

Diagram shown in the original SVG worksheet.

(a) Method and calculation

bθ̇=pEsin⁡δ,δ̇=ω−pEbsin⁡δ.b\dot\theta=pE\sin\delta,\quad\dot\delta=\omega-\frac{pE}{b}\sin\delta.δ̇=0⇒sin⁡δ=bωpE,ω≤ωc=pEb.\dot\delta=0\Rightarrow\sin\delta=\frac{b\omega}{pE},\quad\omega\le\omega_c=\frac{pE}{b}.

(b) Interpretation and further calculation

δs=sin⁡−1(.600)≈36.8699∘,P=bθ̇2=bω2.\delta_s=\sin^{-1}(.600)\approx36.8699^\circ,\quad P=b\dot\theta^2=b\omega^2.δ=δs+η:η̇≃−pEbcos⁡δsη.\delta=\delta_s+\eta:\quad\dot\eta\simeq-\frac{pE}{b}\cos\delta_s\,\eta.The branch with cos⁡δs>0\cos\delta_s>0 is stable; the supplementary branch is unstable. At the threshold the two branches meet and linear restoring relaxation vanishes.

Physical check

Although the angle between moment and field is constant in synchronous motion, the external field drive continually supplies dissipated mechanical energy.