A Point Charge in an Electric Field — Question 4

Section 22-7 · Physics pages 3598–3599

Question 4 A linear restoring field produces harmonic motion for only one charge sign Along a constrained frictionless x axis, the prescribed field is Ex = −κx, with κ > 0. A particle of mass m and charge q starts at x = A > 0 from rest. The constraint prevents transverse motion and does no work. x 0 Schematic; labels, not drawing lengths, specify the data. (a) For q > 0, derive the angular frequency, motion and maximum speed. (b) For q < 0, solve the initial-value equation and classify the equilibrium.
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Question 4 - Solution A linear restoring field produces harmonic motion for only one charge sign x 0 (a) Method and calculation m¨x = −qκx, ω = √ qκ/m. x(t) = A cos ωt, v(t) = −Aω sin ωt, vmax = Aω. (b) Interpretation and further calculation q < 0 : ¨x = Ω2x, Ω= √ |q|κ/m. x(t) = A cosh Ωt, v(t) = AΩsinh Ωt. Positive charge has a restoring force in this constrained direction; negative charge is driven away from the origin. Physical check This one-dimensional model makes no claim of stable trapping in unconstrained three-dimensional space.

Question 4

A linear restoring field produces harmonic motion for only one charge sign

Along a constrained frictionless x axis, the prescribed field is Ex=−κxE_x=-\kappa x, with κ>0\kappa>0. A particle of mass m and charge q starts at x=A>0x=A>0 from rest. The constraint prevents transverse motion and does no work.

Diagram shown in the original SVG worksheet.

  1. For q>0q>0, derive the angular frequency, motion and maximum speed.

  2. For q<0q<0, solve the initial-value equation and classify the equilibrium.

Question 4 - Solution

A linear restoring field produces harmonic motion for only one charge sign

Diagram shown in the original SVG worksheet.

(a) Method and calculation

mẍ=−qκx,ω=qκ/m.m\ddot x=-q\kappa x,\quad\omega=\sqrt{q\kappa/m}.x(t)=Acos⁡ωt,v(t)=−Aωsin⁡ωt,vmax=Aω.x(t)=A\cos\omega t,\quad v(t)=-A\omega\sin\omega t,\quad v_{\max}=A\omega.

(b) Interpretation and further calculation

q<0:ẍ=Ω2x,Ω=|q|κ/m.q<0:\quad\ddot x=\Omega^2x,\quad\Omega=\sqrt{|q|\kappa/m}.x(t)=Acosh⁡Ωt,v(t)=AΩsinh⁡Ωt.x(t)=A\cosh\Omega t,\quad v(t)=A\Omega\sinh\Omega t.Positive charge has a restoring force in this constrained direction; negative charge is driven away from the origin.

Physical check

This one-dimensional model makes no claim of stable trapping in unconstrained three-dimensional space.