The Electric Field Due to a Line of Charge — Question 8

Section 22-5 · Physics pages 3566–3567

Question 8 A ring field on its axis follows from projection of every charge element A uniformly charged thin ring of radius R and total charge Q lies in the xy plane. Find its field on the z axis for z > 0. Use Coulomb constant k. z P Schematic; labels, not drawing lengths, specify the data. (a) Derive the axial field by integrating charge elements at their common distance. (b) Find its small-z and large-z limits and explain why replacing the ring by a central point charge fails near the center.
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Question 8 - Solution A ring field on its axis follows from projection of every charge element z P (a) Method and calculation r = √ R2 + z2, dEz = k dq r2 z r . Ex = Ey = 0, Ez = kQz (R2 + z2)3/2 . (b) Interpretation and further calculation z ≪R : Ez ≃(kQ/R3)z →0. z ≫R : Ez ≃kQ/z2. A point replacement diverges as z →0, while the actual ring field vanishes by symmetry. Physical check All ring elements are equally far from P, but the axial projection factor is still required.

Question 8

A ring field on its axis follows from projection of every charge element

A uniformly charged thin ring of radius R and total charge Q lies in the xy plane. Find its field on the z axis for z>0z>0. Use Coulomb constant k.

Diagram shown in the original SVG worksheet.

  1. Derive the axial field by integrating charge elements at their common distance.

  2. Find its small-z and large-z limits and explain why replacing the ring by a central point charge fails near the center.

Question 8 - Solution

A ring field on its axis follows from projection of every charge element

Diagram shown in the original SVG worksheet.

(a) Method and calculation

r=R2+z2,dEz=kdqr2zr.r=\sqrt{R^2+z^2},\quad dE_z=\frac{k\,dq}{r^2}\frac zr.Ex=Ey=0,Ez=kQz(R2+z2)3/2.E_x=E_y=0,\quad E_z=\frac{kQz}{(R^2+z^2)^{3/2}}.

(b) Interpretation and further calculation

z≪R:Ez≃(kQ/R3)z→0.z\ll R:\quad E_z\simeq(kQ/R^3)z\to0.z≫R:Ez≃kQ/z2.z\gg R:\quad E_z\simeq kQ/z^2.A point replacement diverges as z→0z\to0, while the actual ring field vanishes by symmetry.

Physical check

All ring elements are equally far from P, but the axial projection factor is still required.