The Electric Field Due to an Electric Dipole — Question 3

Section 22-4 · Physics pages 3536–3537

Question 3 An axial approximation needs a quantified distance criterion For the finite dipole at x > a, use Eexact = (2kp/x3)(1 −a2/x2)−2 and approximation Ed = 2kp/x3. Define relative error as (Eexact −Ed)/Eexact. x −q +q P Schematic; labels, not drawing lengths, specify the data. (a) Derive the error as a function of u = a/x. (b) Find the minimum x/a for error no greater than 1.00 percent and identify whether the approximation overestimates or underestimates the exact field.
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Question 3 - Solution An axial approximation needs a quantified distance criterion x −q +q P (a) Method and calculation ϵ = 1 − Ed Eexact = 1 −(1 −u2)2 = 2u2 −u4. ϵ ≤.0100 ⇒(1 −u2)2 ≥.9900. (b) Interpretation and further calculation 0 < u < 1 : u2 ≤1 − √ .9900. x/a ≥[1 − √ .9900]−1/2 ≈14.1244. The exact multiplier exceeds one, so the point-dipole approximation underestimates the axial field. Physical check An error percentage is ambiguous unless its denominator is stated.

Question 3

An axial approximation needs a quantified distance criterion

For the finite dipole at x>ax>a, use Eexact=(2kp/x3)(1−a2/x2)−2E_{\mathrm{exact}}=(2kp/x^3)(1-a^2/x^2)^{-2} and approximation Ed=2kp/x3E_d=2kp/x^3. Define relative error as (Eexact−Ed)/Eexact(E_{\mathrm{exact}}-E_d)/E_{\mathrm{exact}}.

Diagram shown in the original SVG worksheet.

  1. Derive the error as a function of u=a/xu=a/x.

  2. Find the minimum x/ax/a for error no greater than 1.00 percent and identify whether the approximation overestimates or underestimates the exact field.

Question 3 - Solution

An axial approximation needs a quantified distance criterion

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ϵ=1−EdEexact=1−(1−u2)2=2u2−u4.\epsilon=1-\frac{E_d}{E_{\mathrm{exact}}}=1-(1-u^2)^2=2u^2-u^4.ϵ≤.0100⇒(1−u2)2≥.9900.\epsilon\le.0100\Rightarrow(1-u^2)^2\ge.9900.

(b) Interpretation and further calculation

0<u<1:u2≤1−.9900.0<u<1:\quad u^2\le1-\sqrt{.9900}.x/a≥[1−.9900]−1/2≈14.1244.x/a\ge[1-\sqrt{.9900}]^{-1/2}\approx14.1244.The exact multiplier exceeds one, so the point-dipole approximation underestimates the axial field.

Physical check

An error percentage is ambiguous unless its denominator is stated.