Charge Is Conserved — Question 9

Section 21-5 · Physics pages 3468–3469

Question 9 Ionization and electron loss have different effects on gas charge An initially neutral gas creates 1200 singly positive ion–electron pairs per second. Recombination removes 400 such pairs per second. Additionally, 600 electrons per second escape to an initially neutral collecting wall; no ions escape. Rates are constant for one second and the supplied counts are feasible throughout that interval. gas: ion–electron pairs e− wall Schematic; labels, not drawing lengths, specify the data. (a) Find the ion and free-electron populations added to the gas during the second and its final net charge. (b) Find the wall charge and the combined total. Write a general balance showing why pair creation and recombination cancel out of the gas net-charge rate.
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Question 9 - Solution Ionization and electron loss have different effects on gas charge gas: ion–electron pairs e− wall (a) Method and calculation ∆Ni = 1200 −400 = 800, ∆Ne = 1200 −400 −600 = 200. ∆Qgas = e(800 −200) = +600e, ∆Qwall = −600e. (b) Interpretation and further calculation ˙Qgas = e[(G −R) −(G −R −L)] = eL. ∆(Qgas + Qwall) = 0. Generating or recombining a positive ion and an electron changes charged-particle counts without changing net charge. Selective electron escape changes the gas subsystem charge. Physical check The wall must be included when testing conservation for the complete gas-and-collector system.

Question 9

Ionization and electron loss have different effects on gas charge

An initially neutral gas creates 1200 singly positive ion–electron pairs per second. Recombination removes 400 such pairs per second. Additionally, 600 electrons per second escape to an initially neutral collecting wall; no ions escape. Rates are constant for one second and the supplied counts are feasible throughout that interval.

Diagram shown in the original SVG worksheet.

  1. Find the ion and free-electron populations added to the gas during the second and its final net charge.

  2. Find the wall charge and the combined total. Write a general balance showing why pair creation and recombination cancel out of the gas net-charge rate.

Question 9 - Solution

Ionization and electron loss have different effects on gas charge

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ΔNi=1200−400=800,ΔNe=1200−400−600=200.\Delta N_i=1200-400=800,\quad\Delta N_e=1200-400-600=200.ΔQgas=e(800−200)=+600e,ΔQwall=−600e.\Delta Q_{\mathrm{gas}}=e(800-200)=+600e,\quad\Delta Q_{\mathrm{wall}}=-600e.

(b) Interpretation and further calculation

Q̇gas=e[(G−R)−(G−R−L)]=eL.\dot Q_{\mathrm{gas}}=e[(G-R)-(G-R-L)]=eL.Δ(Qgas+Qwall)=0.\Delta(Q_{\mathrm{gas}}+Q_{\mathrm{wall}})=0.Generating or recombining a positive ion and an electron changes charged-particle counts without changing net charge. Selective electron escape changes the gas subsystem charge.

Physical check

The wall must be included when testing conservation for the complete gas-and-collector system.