Charge Is Quantized — Question 4

Section 21-4 · Physics pages 3438–3439

Question 4 Observed charge steps give an upper candidate for the basic unit A device shows exact charge levels 0, 6u, 10u, 16u, where u > 0 is a known calibration unit. Suppose each level is an integer multiple of an unknown positive elementary step q0. No claim is made that the device has visited every allowed level. Q/u 0 6 10 16 Schematic; labels, not drawing lengths, specify the data. (a) Find the largest possible q0 consistent with all four levels and show explicitly the corresponding integer labels. (b) Explain why the data do not prove this largest candidate is the true smallest step. Determine how a later level 7u changes the largest candidate.
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Question 4 - Solution Observed charge steps give an upper candidate for the basic unit Q/u 0 6 10 16 (a) Method and calculation qmax 0 = gcd(6, 10, 16)u = 2u. (0, 6u, 10u, 16u) = (0, 3, 5, 8)(2u). (b) Interpretation and further calculation q0 = 2u/m, m = 1, 2, 3, . . . also fits the original data. gcd(6, 10, 16, 7)u = u. A missing smaller step can reflect limited sampling or restricted transfer processes. The added odd level excludes 2u but still permits subdivisions of u. Physical check This exact greatest-common-divisor inference would need an explicit tolerance model for noisy measurements.

Question 4

Observed charge steps give an upper candidate for the basic unit

A device shows exact charge levels 0,6u,10u,16u0,6u,10u,16u, where u>0u>0 is a known calibration unit. Suppose each level is an integer multiple of an unknown positive elementary step q0q_0. No claim is made that the device has visited every allowed level.

Diagram shown in the original SVG worksheet.

  1. Find the largest possible q0q_0 consistent with all four levels and show explicitly the corresponding integer labels.

  2. Explain why the data do not prove this largest candidate is the true smallest step. Determine how a later level 7u7u changes the largest candidate.

Question 4 - Solution

Observed charge steps give an upper candidate for the basic unit

Diagram shown in the original SVG worksheet.

(a) Method and calculation

q0max=gcd⁡(6,10,16)u=2u.q_0^{\max}=\gcd(6,10,16)u=2u.(0,6u,10u,16u)=(0,3,5,8)(2u).(0,6u,10u,16u)=(0,3,5,8)(2u).

(b) Interpretation and further calculation

q0=2u/m,m=1,2,3,…also fits the original data.q_0=2u/m,\qquad m=1,2,3,\ldots\quad\text{also fits the original data}.gcd⁡(6,10,16,7)u=u.\gcd(6,10,16,7)u=u.A missing smaller step can reflect limited sampling or restricted transfer processes. The added odd level excludes 2u2u but still permits subdivisions of uu.

Physical check

This exact greatest-common-divisor inference would need an explicit tolerance model for noisy measurements.