The Efficiencies of Real Engines — Question 6

Section 20-6 · Physics pages 3342–3343

Question 6 Compressor work must be subtracted from turbine work in a gas-turbine cycle In an ideal Brayton model, compression 1 to 2 and expansion 3 to 4 are reversible adiabatic, with common pressure ratio rp = 9 and γ = 1.40. Heat addition 2 to 3 and rejection 4 to 1 occur at constant pressure. Use T1 = 300 K, T3 = 1200 K, cp = 1.00 kJ/(kg K), and a = r(γ−1)/γ p . compressor heater turbine shaft power to compressor Schematic; labels, not drawing lengths, specify the data. (a) Find temperatures T2 = aT1, T4 = T3/a, compressor and turbine specific works, and net specific work. (b) Derive efficiency and the range of a > 1 needed for positive net work.
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Question 6 - Solution Compressor work must be subtracted from turbine work in a gas-turbine cycle compressor heater turbine shaft power to compressor (a) Method and calculation a = 92/7 ≈1.87344, T2 ≈562.033 K, T4 ≈640.532 K. wc = cp(T2 −T1) ≈262.033, wt = cp(T3 −T4) ≈559.468 kJ/kg. wnet = wt −wc ≈297.435 kJ/kg. (b) Interpretation and further calculation qh = cp(T3 −aT1), wnet = cp(a −1)(T3/a −T1). η = wnet/qh = 1 −1/a ≈.466224, wnet > 0 ⇔1 < a < T3/T1 = 4. A turbine can deliver substantial gross work while the compressor consumes much of it. Physical check At the upper limit, the temperature available for external heat addition vanishes along with net work.

Question 6

Compressor work must be subtracted from turbine work in a gas-turbine cycle

In an ideal Brayton model, compression 1 to 2 and expansion 3 to 4 are reversible adiabatic, with common pressure ratio rp=9r_p=9 and γ=1.40\gamma=1.40. Heat addition 2 to 3 and rejection 4 to 1 occur at constant pressure. Use T1=300T_1=300 K, T3=1200T_3=1200 K, cp=1.00c_p=1.00 kJ/(kg K), and a=rp(γ−1)/γa=r_p^{(\gamma-1)/\gamma}.

Diagram shown in the original SVG worksheet.

  1. Find temperatures T2=aT1T_2=aT_1, T4=T3/aT_4=T_3/a, compressor and turbine specific works, and net specific work.

  2. Derive efficiency and the range of a>1a>1 needed for positive net work.

Question 6 - Solution

Compressor work must be subtracted from turbine work in a gas-turbine cycle

Diagram shown in the original SVG worksheet.

(a) Method and calculation

a=92/7≈1.87344,T2≈562.033K,T4≈640.532K.a=9^{2/7}\approx1.87344,\quad T_2\approx562.033\,\mathrm K,\quad T_4\approx640.532\,\mathrm K.wc=cp(T2−T1)≈262.033,wt=cp(T3−T4)≈559.468kJ/kg.w_c=c_p(T_2-T_1)\approx262.033,\quad w_t=c_p(T_3-T_4)\approx559.468\quad\mathrm{kJ/kg}.wnet=wt−wc≈297.435kJ/kg.w_{\mathrm{net}}=w_t-w_c\approx297.435\,\mathrm{kJ/kg}.

(b) Interpretation and further calculation

qh=cp(T3−aT1),wnet=cp(a−1)(T3/a−T1).q_h=c_p(T_3-aT_1),\quad w_{\mathrm{net}}=c_p(a-1)(T_3/a-T_1).η=wnet/qh=1−1/a≈.466224,wnet>0⇔1<a<T3/T1=4.\eta=w_{\mathrm{net}}/q_h=1-1/a\approx.466224,\quad w_{\mathrm{net}}>0\ \Leftrightarrow\ 1<a<T_3/T_1=4.A turbine can deliver substantial gross work while the compressor consumes much of it.

Physical check

At the upper limit, the temperature available for external heat addition vanishes along with net work.