The Efficiencies of Real Engines — Question 4

Section 20-6 · Physics pages 3338–3339

Question 4 The ideal Otto model isolates the effect of compression ratio An idealized Otto cycle has two reversible adiabatic legs and two constant-volume heat-transfer legs. States 1 to 2 compress by r = V1/V2 = 8; 2 to 3 heat at fixed volume; 3 to 4 expand back to V1; 4 to 1 cool at fixed volume. Use constant γ = 1.40, T1 = 300 K and T3 = 1800 K. V p 1 2 3 4 Axes and labels specify the model; the sketch is schematic. (a) Find T2, T4 using TV γ−1 = constant and derive the cycle efficiency from the two constant-volume heats. (b) Evaluate efficiency and compare it with the Carnot bound based on the extreme temperatures. Explain why the idealized cycle is not a prediction for a real engine.
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Question 4 - Solution The ideal Otto model isolates the effect of compression ratio V p 1 2 3 4 (a) Method and calculation a = rγ−1 = 8.4 ≈2.29740, T2 = aT1 ≈689.219 K, T4 = T3/a ≈783.496 K. η = 1 −nCV (T4 −T1) nCV (T3 −T2) = 1 −1 a. (b) Interpretation and further calculation η ≈.564725, ηCarnot,extremes = 1 −300/1800 = 5/6. .564725 < .833333. Heat enters over varying gas temperatures. Real operation also departs from constant capacities, reversible compression and expansion, and the specified ideal heat-transfer model. Physical check The simplified efficiency depends on compression ratio only because its other model parameters are held fixed.

Question 4

The ideal Otto model isolates the effect of compression ratio

An idealized Otto cycle has two reversible adiabatic legs and two constant-volume heat-transfer legs. States 1 to 2 compress by r=V1/V2=8r=V_1/V_2=8; 2 to 3 heat at fixed volume; 3 to 4 expand back to V1V_1; 4 to 1 cool at fixed volume. Use constant γ=1.40\gamma=1.40, T1=300T_1=300 K and T3=1800T_3=1800 K.

Diagram shown in the original SVG worksheet.

  1. Find T2,T4T_2,T_4 using TVγ−1=constantTV^{\gamma-1}=\text{constant} and derive the cycle efficiency from the two constant-volume heats.

  2. Evaluate efficiency and compare it with the Carnot bound based on the extreme temperatures. Explain why the idealized cycle is not a prediction for a real engine.

Question 4 - Solution

The ideal Otto model isolates the effect of compression ratio

Diagram shown in the original SVG worksheet.

(a) Method and calculation

a=rγ−1=8.4≈2.29740,T2=aT1≈689.219K,T4=T3/a≈783.496K.a=r^{\gamma-1}=8^{.4}\approx2.29740,\quad T_2=aT_1\approx689.219\,\mathrm K,\quad T_4=T_3/a\approx783.496\,\mathrm K.η=1−nCV(T4−T1)nCV(T3−T2)=1−1a.\eta=1-\frac{nC_V(T_4-T_1)}{nC_V(T_3-T_2)}=1-\frac1a.

(b) Interpretation and further calculation

η≈.564725,ηCarnot,extremes=1−300/1800=5/6.\eta\approx.564725,\quad\eta_{\mathrm{Carnot,extremes}}=1-300/1800=5/6..564725<.833333..564725<.833333.Heat enters over varying gas temperatures. Real operation also departs from constant capacities, reversible compression and expansion, and the specified ideal heat-transfer model.

Physical check

The simplified efficiency depends on compression ratio only because its other model parameters are held fixed.