The Second Law of Thermodynamics — Question 10

Section 20-3 · Physics pages 3290–3291

Question 10 Measurement intervals can straddle the second-law feasibility boundary A cyclic device has zero net internal-energy and entropy changes. Take heat magnitudes Qh, Qc > 0 for absorption from a hot reservoir and rejection to a cold one. Then W = Qh −Qc and Sgen = Qc/Tc −Qh/Th ≥0. Heat measurements give Qh = 1000 ± 10 J and Qc = 590 ± 10 J, where the intervals are hard bounds. Reservoir temperatures are exactly 500 K and 300 K. No correlation between heat errors is specified. Qh Qc Qc = .600Qh Axes and labels specify the model; the sketch is schematic. (a) Calculate nominal entropy generation and its full allowed interval. (b) Can these data conclusively establish a second-law violation? State the boundary between compatible and incompatible heat pairs.
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Question 10 - Solution Measurement intervals can straddle the second-law feasibility boundary Qh Qc Qc = .600Qh (a) Method and calculation Sgen,0 = 590/300 −1000/500 = −1/30 J/K. Smin = 580/300 −1010/500 = −.0866667, Smax = 600/300 −990/500 = .0200 J/K. (b) Interpretation and further calculation Sgen ≥0 ⇔Qc ≥(Tc/Th)Qh = .600Qh. Smin < 0 < Smax. The nominal point is incompatible, but feasible pairs remain within the stated bounds. Better precision or additional information is needed to establish a violation of the assumed device model. Physical check An uncertainty interval is not a probability distribution, so it does not assign a probability of violation.

Question 10

Measurement intervals can straddle the second-law feasibility boundary

A cyclic device has zero net internal-energy and entropy changes. Take heat magnitudes Qh,Qc>0Q_h,Q_c>0 for absorption from a hot reservoir and rejection to a cold one. Then W=Qh−QcW=Q_h-Q_c and Sgen=Qc/Tc−Qh/Th≥0S_{\mathrm{gen}}=Q_c/T_c-Q_h/T_h\ge0. Heat measurements give Qh=1000±10Q_h=1000\pm10 J and Qc=590±10Q_c=590\pm10 J, where the intervals are hard bounds. Reservoir temperatures are exactly 500 K and 300 K. No correlation between heat errors is specified.

Diagram shown in the original SVG worksheet.

  1. Calculate nominal entropy generation and its full allowed interval.

  2. Can these data conclusively establish a second-law violation? State the boundary between compatible and incompatible heat pairs.

Question 10 - Solution

Measurement intervals can straddle the second-law feasibility boundary

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Sgen,0=590/300−1000/500=−1/30J/K.S_{{\mathrm{gen}},0}=590/300-1000/500=-1/30\,\mathrm{J/K}.Smin=580/300−1010/500=−.0866667,Smax=600/300−990/500=.0200J/K.S_{\min}=580/300-1010/500=-.0866667,\quad S_{\max}=600/300-990/500=.0200\quad\mathrm{J/K}.

(b) Interpretation and further calculation

Sgen≥0⇔Qc≥(Tc/Th)Qh=.600Qh.S_{\mathrm{gen}}\ge0\ \Leftrightarrow\ Q_c\ge(T_c/T_h)Q_h=.600Q_h.Smin<0<Smax.S_{\min}<0<S_{\max}.The nominal point is incompatible, but feasible pairs remain within the stated bounds. Better precision or additional information is needed to establish a violation of the assumed device model.

Physical check

An uncertainty interval is not a probability distribution, so it does not assign a probability of violation.