Acceleration — Question 4

Section 2-5 · Physics pages 218–219

Question 4 Zero acceleration is not a complete description of motion Three exact local velocity histories near t = 2 s are vA(t) = 4 + (t −2)3, vB(t) = (t −2)2, vC(t) = 2(t −2). In these formulas t is numerical seconds and velocities are numerical m/s. Differentiate using d[(t −c)n]/dt = n(t −c)n−1 to obtain acceleration in m/s2. Examine a sufficiently small neighborhood of 2 s. t t = 2 A t t = 2 B t t = 2 C 4 0 0 Schematic local velocity shapes, with independent vertical scales. A is shown relative to 4 m/s; B and C relative to zero. (a) Find velocity, speed and acceleration at 2 s for each history. (b) Which histories have a direction reversal at 2 s? Which are instantaneously at rest there? Does either condition require acceleration to vanish? (c) A student claims that zero acceleration always means a local maximum or minimum of velocity. Test this claim using A and B. (d) Does zero acceleration at one instant imply constant speed on a surrounding interval? Contrast A with a fourth history vD(t) = 4 m/s throughout that interval. (e) Explain why the pair of readings v = 0, a = 0 at one instant does not establish that an object remains at rest for any duration.
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Question 4 - Solution Zero acceleration is not a complete description of motion t t = 2 A t t = 2 B t t = 2 C 4 0 0 (a) Differentiate each history and evaluate at the same instant. aA = 3(t −2)2, aB = 2(t −2), aC = 2 (m/s2). The accelerations are aA = 3(t −2)2, aB = 2(t −2) and aC = 2, in m/s2 under the stated numerical convention. (vA, sA, aA)t=2 = (4 m/s, 4 m/s, 0), (vB, sB, aB)t=2 = (0, 0, 0), (vC, sC, aC)t=2 = (0, 0, 2 m/s2). (b) Test direction using nearby velocity signs. A is eastward on both sides sufficiently close to 2 s. B is also eastward on both sides, with an isolated zero velocity at 2 s. C changes from westward to eastward and reverses. B and C are instantaneously at rest; only C reverses. C’s nonzero acceleration shows that neither instantaneous rest nor reversal requires zero acceleration. (c) A zero slope need not create an extremum. For A, velocity is below 4 m/s just before 2 s and above 4 m/s just after. It increases through a horizontal tangent, with neither a local maximum nor a local minimum. B does have a local minimum of velocity at 2 s. Both have zero acceleration there, so that single condition does not decide whether a velocity extremum occurs. (d) An isolated zero derivative is weaker than a constant function. A’s speed changes through 2 s even though its instantaneous acceleration there is zero. D instead has constant velocity and speed on the entire interval, with zero acceleration at every interior instant. At 2 s A and D have identical velocity and acceleration, but their neighboring histories differ. (e) Two local readings still leave surrounding motion undetermined. vB(2) = aB(2) = 0, vB(2 + h) = h2 > 0 (h̸ = 0). B supplies a counterexample to the claim of sustained rest: vB(2) = aB(2) = 0, but vB(t) > 0 for every nearby t̸ = 2. A history identically at rest would have the same pair of readings. Establishing rest over a duration requires information across that interval, not only values at one instant.

Question 4

Zero acceleration is not a complete description of motion

Three exact local velocity histories near t=2st=2\ \mathrm{s} are vA(t)=4+(t−2)3,vB(t)=(t−2)2,vC(t)=2(t−2).v_A(t)=4+(t-2)^3,\qquad v_B(t)=(t-2)^2,\qquad v_C(t)=2(t-2). In these formulas tt is numerical seconds and velocities are numerical m/s. Differentiate using d[(t−c)n]/dt=n(t−c)n−1d[(t-c)^n]/dt=n(t-c)^{n-1} to obtain acceleration in m/s2\mathrm{m/s^2}. Examine a sufficiently small neighborhood of 2 s.

Diagram shown in the original SVG worksheet.

  1. Find velocity, speed and acceleration at 2 s for each history.

  2. Which histories have a direction reversal at 2 s? Which are instantaneously at rest there? Does either condition require acceleration to vanish?

  3. A student claims that zero acceleration always means a local maximum or minimum of velocity. Test this claim using A and B.

  4. Does zero acceleration at one instant imply constant speed on a surrounding interval? Contrast A with a fourth history vD(t)=4m/sv_D(t)=4\ \mathrm{m/s} throughout that interval.

  5. Explain why the pair of readings v=0,a=0v=0,a=0 at one instant does not establish that an object remains at rest for any duration.

Question 4 - Solution

Zero acceleration is not a complete description of motion

Diagram shown in the original SVG worksheet.

(a) Differentiate each history and evaluate at the same instant.

aA=3(t−2)2,aB=2(t−2),aC=2(m/s2).a_A=3(t-2)^2,\qquad a_B=2(t-2),\qquad a_C=2\quad(\mathrm{m/s^2}).

The accelerations are aA=3(t−2)2a_A=3(t-2)^2, aB=2(t−2)a_B=2(t-2) and aC=2a_C=2, in m/s2\mathrm{m/s^2} under the stated numerical convention. (vA,sA,aA)t=2=(4m/s,4m/s,0),(vB,sB,aB)t=2=(0,0,0),(vC,sC,aC)t=2=(0,0,2m/s2).\begin{aligned}(v_A,s_A,a_A)_{t=2}&=(4\ \mathrm{m/s},4\ \mathrm{m/s},0),\\(v_B,s_B,a_B)_{t=2}&=(0,0,0),\\(v_C,s_C,a_C)_{t=2}&=(0,0,2\ \mathrm{m/s^2}).\end{aligned}

(b) Test direction using nearby velocity signs.

A is eastward on both sides sufficiently close to 2 s. B is also eastward on both sides, with an isolated zero velocity at 2 s. C changes from westward to eastward and reverses. B and C are instantaneously at rest; only C reverses. C’s nonzero acceleration shows that neither instantaneous rest nor reversal requires zero acceleration.

(c) A zero slope need not create an extremum.

For A, velocity is below 4 m/s just before 2 s and above 4 m/s just after. It increases through a horizontal tangent, with neither a local maximum nor a local minimum. B does have a local minimum of velocity at 2 s. Both have zero acceleration there, so that single condition does not decide whether a velocity extremum occurs.

(d) An isolated zero derivative is weaker than a constant function.

A’s speed changes through 2 s even though its instantaneous acceleration there is zero. D instead has constant velocity and speed on the entire interval, with zero acceleration at every interior instant. At 2 s A and D have identical velocity and acceleration, but their neighboring histories differ.

(e) Two local readings still leave surrounding motion undetermined.

vB(2)=aB(2)=0,vB(2+h)=h2>0(h≠0).v_B(2)=a_B(2)=0,\qquad v_B(2+h)=h^2>0\quad(h\ne0).

B supplies a counterexample to the claim of sustained rest: vB(2)=aB(2)=0v_B(2)=a_B(2)=0, but vB(t)>0v_B(t)>0 for every nearby t≠2t\ne2. A history identically at rest would have the same pair of readings. Establishing rest over a duration requires information across that interval, not only values at one instant.