Motion — Question 5

Section 2-1 · Physics pages 140–141

Question 5 A moving image is not always a moving object A camera views a straight track with fixed landmarks A and B, separated by 4.00 m. P is the tracked object. The image may shift horizontally between exposures, but the initial model excludes rescaling and distortion. All three points lie in the same calibrated plane. I A: 100 B: 500 P: 260 II A: 140 B: 540 P: 300 III A: 120 B: 520 P: 360 Three image rows. Positions follow the pixel data; A and B are fixed track landmarks. Pixel locations increase to the right and are exact in this model: The pixel coordinates (A, P, B) are (100, 260, 500) in image I, (140, 300, 540) in image II, and (120, 360, 520) in image III. The fraction of the A-to-B span occupied by P is f = (pP −pA)/(pB −pA). (a) Compute f in each image. Does P change its recorded location relative to the track between I and II? Between II and III? (b) Find P’s distance from A in each image. Explain why the raw pixel change of P alone would give a misleading account of I to II. (c) In a fourth image, A and B are 450 pixels apart. Is the original pure-shift model still adequate? Does this observation alone establish that the physical landmarks moved? (d) Do equal track-relative locations in I and II prove P stayed at rest throughout the intervening interval? State the limit of the conclusion.
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Question 5 - Solution A moving image is not always a moving object I A: 100 B: 500 P: 260 II A: 140 B: 540 P: 300 III A: 120 B: 520 P: 360 (a) Remove the common image offset with landmarks. f = pP −pA pB −pA : fI = 160 400 = 0.4, fII = 160 400 = 0.4, fIII = 240 400 = 0.6. The landmark separation is 400 px in each of the first three images. Thus fI = 260 −100 400 = 0.40 , fII = 300 −140 400 = 0.40 , fIII = 360 −120 400 = 0.60 . P has the same recorded track-relative location in I and II. In III it is farther toward B. (b) Use the physical landmark span. xP/A = 4f m : (1.6, 1.6, 2.4) m; ∆xII→III = +0.8 m. Multiplying by 4.00 m gives distances from A of 1.60, 1.60, 2.40 m . The sampled change from II to III is 0.80 m toward B. Between I and II, A, P, and B all shift by 40 px. That common image shift changes P’s raw pixel coordinate without changing its location relative to the landmarks. Treating the image origin as fixed to the track would misidentify camera/image motion as object motion. (c) Test the image model before interpreting a new record. p′ B −p′ A = (pB + c) −(pA + c) = pB −pA = 400̸ = 450. A pure horizontal shift preserves the A–B pixel separation. A change from 400 to 450 px therefore contradicts that model. Rescaling, changed viewing geometry, or another image-model failure could explain it while the landmarks remain physically fixed. Physical landmark motion is not established by the pixel span alone. (d) Registration does not fill gaps in time. The equal fractions establish equal track-relative locations at two exposure instants. P could move and return between them. Landmarks resolve the image-reference issue; they do not turn separate snapshots into continuous monitoring of P.

Question 5

A moving image is not always a moving object

A camera views a straight track with fixed landmarks A and B, separated by 4.00m4.00\ \mathrm{m}. P is the tracked object. The image may shift horizontally between exposures, but the initial model excludes rescaling and distortion. All three points lie in the same calibrated plane.

Diagram shown in the original SVG worksheet.

Pixel locations increase to the right and are exact in this model: The pixel coordinates (A,P,B)(A,P,B) are (100,260,500)(100,260,500) in image I, (140,300,540)(140,300,540) in image II, and (120,360,520)(120,360,520) in image III. The fraction of the A-to-B span occupied by P is f=(pP−pA)/(pB−pA)f=(p_P-p_A)/(p_B-p_A).

  1. Compute ff in each image. Does P change its recorded location relative to the track between I and II? Between II and III?

  2. Find P’s distance from A in each image. Explain why the raw pixel change of P alone would give a misleading account of I to II.

  3. In a fourth image, A and B are 450 pixels apart. Is the original pure-shift model still adequate? Does this observation alone establish that the physical landmarks moved?

  4. Do equal track-relative locations in I and II prove P stayed at rest throughout the intervening interval? State the limit of the conclusion.

Question 5 - Solution

A moving image is not always a moving object

Diagram shown in the original SVG worksheet.

(a) Remove the common image offset with landmarks.

f=pP−pApB−pA:fI=160400=0.4,fII=160400=0.4,fIII=240400=0.6.f=\frac{p_P-p_A}{p_B-p_A}:\quad f_I=\frac{160}{400}=0.4,\quad f_{II}=\frac{160}{400}=0.4,\quad f_{III}=\frac{240}{400}=0.6.

The landmark separation is 400 px in each of the first three images. Thus fI=260−100400=0.40,fII=300−140400=0.40,fIII=360−120400=0.60.f_I=\frac{260-100}{400}=\boxed{0.40},\quad f_{II}=\frac{300-140}{400}=\boxed{0.40},\quad f_{III}=\frac{360-120}{400}=\boxed{0.60}. P has the same recorded track-relative location in I and II. In III it is farther toward B.

(b) Use the physical landmark span.

xP/A=4fm:(1.6,1.6,2.4)m;ΔxII→III=+0.8m.x_{P/A}=4f\ \mathrm{m}:\quad(1.6,1.6,2.4)\ \mathrm{m};\qquad\Delta x_{II\to III}=+0.8\ \mathrm{m}.

Multiplying by 4.00 m gives distances from A of 1.60,1.60,2.40m\boxed{1.60,\ 1.60,\ 2.40\ \mathrm{m}}. The sampled change from II to III is 0.80 m toward B.

Between I and II, A, P, and B all shift by 40 px. That common image shift changes P’s raw pixel coordinate without changing its location relative to the landmarks. Treating the image origin as fixed to the track would misidentify camera/image motion as object motion.

(c) Test the image model before interpreting a new record.

pB′−pA′=(pB+c)−(pA+c)=pB−pA=400≠450.p'_B-p'_A=(p_B+c)-(p_A+c)=p_B-p_A=400\ne450.

A pure horizontal shift preserves the A–B pixel separation. A change from 400 to 450 px therefore contradicts that model. Rescaling, changed viewing geometry, or another image-model failure could explain it while the landmarks remain physically fixed. Physical landmark motion is not established by the pixel span alone.

(d) Registration does not fill gaps in time.

The equal fractions establish equal track-relative locations at two exposure instants. P could move and return between them. Landmarks resolve the image-reference issue; they do not turn separate snapshots into continuous monitoring of P.