Degrees of Freedom and Molar Specific Heats — Question 4

Section 19-8 · Physics pages 3178–3179

Question 4 A measured heat-capacity ratio constrains an effective mode count Use classical equipartition: each active independent quadratic energy term contributes 1 2kBT per molecule. Let f count these terms, so for constant f, CV = fR/2, Cp = CV + R and γ = Cp/CV . Take R = 8.314 J/(mol K). A gas has measured γ = 1.400 with a hard uncertainty interval 1.390 ≤γ ≤1.410. Assume the stated ideal-gas relation between capacities. γ −1 f Axes and labels specify the model; the sketch is schematic. (a) Infer central f and the exact corresponding interval of effective f. (b) Can f ≈5 alone prove that the sample is a pure rigid diatomic gas? Give a classical mixture of f = 3 and f = 6 species with the same central effective count.
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Question 4 - Solution A measured heat-capacity ratio constrains an effective mode count γ −1 f (a) Method and calculation γ = 1 + 2 f ⇒f = 2 γ −1. f0 = 5.000, 2 .410 ≤f ≤ 2 .390 ⇒4.87805 ≤f ≤5.12821. (b) Interpretation and further calculation fmix = (1 −x)(3) + x(6) = 5 ⇒x = 2/3. CV,mix = 5 2R, γmix = 7 5. A heat-capacity measurement constrains an energy response. Mixtures and partially active internal modes can share that response, so molecular identity is not uniquely determined. Physical check The inverse relationship makes symmetric uncertainty in γ slightly asymmetric in f.

Question 4

A measured heat-capacity ratio constrains an effective mode count

Use classical equipartition: each active independent quadratic energy term contributes 12kBT\tfrac12k_BT per molecule. Let ff count these terms, so for constant ff, CV=fR/2C_V=fR/2, Cp=CV+RC_p=C_V+R and γ=Cp/CV\gamma=C_p/C_V. Take R=8.314R=8.314 J/(mol K). A gas has measured γ=1.400\gamma=1.400 with a hard uncertainty interval 1.390≤γ≤1.4101.390\le\gamma\le1.410. Assume the stated ideal-gas relation between capacities.

Diagram shown in the original SVG worksheet.

  1. Infer central ff and the exact corresponding interval of effective ff.

  2. Can f≈5f\approx5 alone prove that the sample is a pure rigid diatomic gas? Give a classical mixture of f=3f=3 and f=6f=6 species with the same central effective count.

Question 4 - Solution

A measured heat-capacity ratio constrains an effective mode count

Diagram shown in the original SVG worksheet.

(a) Method and calculation

γ=1+2f⇒f=2γ−1.\gamma=1+\frac2f\ \Rightarrow\ f=\frac2{\gamma-1}.f0=5.000,2.410≤f≤2.390⇒4.87805≤f≤5.12821.f_0=5.000,\quad\frac2{.410}\le f\le\frac2{.390}\ \Rightarrow\ 4.87805\le f\le5.12821.

(b) Interpretation and further calculation

fmix=(1−x)(3)+x(6)=5⇒x=2/3.f_{\mathrm{mix}}=(1-x)(3)+x(6)=5\ \Rightarrow\ x=2/3.CV,mix=52R,γmix=75.C_{V,\mathrm{mix}}=\tfrac52R,\quad\gamma_{\mathrm{mix}}=\tfrac75.A heat-capacity measurement constrains an energy response. Mixtures and partially active internal modes can share that response, so molecular identity is not uniquely determined.

Physical check

The inverse relationship makes symmetric uncertainty in γ\gamma slightly asymmetric in ff.