Translational Kinetic Energy — Question 4

Section 19-4 · Physics pages 3098–3099

Question 4 Pressure-volume data determine translational energy even for a polyatomic gas For equilibrium translational motion use K = 3 2kBT per molecule and Utr = 3 2nRT. Take kB = 1.381 × 10−23 J/K and R = 8.314 J/(mol K). An equilibrium ideal gas occupies .0300 m3 at 200 kPa. Its temperature is not separately measured, and the molecular species may be polyatomic. molecular centers of mass Representative particles; dots do not depict the actual count or scale. (a) Find total translational kinetic energy without first finding temperature or amount. (b) A separate measurement gives total internal energy above the chosen nonkinetic reference as 15.0 kJ. Find the energy assigned to nontranslational modes under an additive internal-energy model. Does 3 2pV determine all internal energy for every gas?
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Question 4 - Solution Pressure-volume data determine translational energy even for a polyatomic gas molecular centers of mass (a) Method and calculation pV = nRT ⇒Utr = 3 2pV. Utr = 3 2(200000)(.0300) = 9000 J. (b) Interpretation and further calculation U = Utr + Uother ⇒Uother = 15000 −9000 = 6000 J. Uother/U = .400. Rotational, vibrational or other specified internal contributions are not included in center-of-mass translational kinetic energy. Physical check The pV identity determines the translational part for a classical ideal gas; additional internal modes require additional information.

Question 4

Pressure-volume data determine translational energy even for a polyatomic gas

For equilibrium translational motion use K¯=32kBT\overline K=\tfrac32k_BT per molecule and Utr=32nRTU_{\mathrm{tr}}=\tfrac32nRT. Take kB=1.381×10−23k_B=1.381\times10^{-23} J/K and R=8.314R=8.314 J/(mol K). An equilibrium ideal gas occupies .0300 m3^3 at 200 kPa. Its temperature is not separately measured, and the molecular species may be polyatomic.

Diagram shown in the original SVG worksheet.

  1. Find total translational kinetic energy without first finding temperature or amount.

  2. A separate measurement gives total internal energy above the chosen nonkinetic reference as 15.0 kJ. Find the energy assigned to nontranslational modes under an additive internal-energy model. Does 32pV\tfrac32pV determine all internal energy for every gas?

Question 4 - Solution

Pressure-volume data determine translational energy even for a polyatomic gas

Diagram shown in the original SVG worksheet.

(a) Method and calculation

pV=nRT⇒Utr=32pV.pV=nRT\ \Rightarrow\ U_{\mathrm{tr}}=\tfrac32pV.Utr=32(200000)(.0300)=9000J.U_{\mathrm{tr}}=\tfrac32(200000)(.0300)=9000\,\mathrm J.

(b) Interpretation and further calculation

U=Utr+Uother⇒Uother=15000−9000=6000J.U=U_{\mathrm{tr}}+U_{\mathrm{other}}\ \Rightarrow\ U_{\mathrm{other}}=15000-9000=6000\,\mathrm J.Uother/U=.400.U_{\mathrm{other}}/U=.400.Rotational, vibrational or other specified internal contributions are not included in center-of-mass translational kinetic energy.

Physical check

The pVpV identity determines the translational part for a classical ideal gas; additional internal modes require additional information.