The Adiabatic Expansion of an Ideal Gas — Question 9

Section 19-10 · Physics pages 3228–3229

Question 9 A confined gas acts as an adiabatic spring for a small piston motion An ideal gas at equilibrium pressure p0 = 100 kPa and volume V0 = .00500 m3 supports a frictionless piston of area A = .0100 m2 and moving mass M = 2.00 kg. External force is constant and balances the equilibrium pressure force. Small displacements are slow enough for uniform gas pressure but fast enough for negligible heat exchange. Take γ = 1.40. gas x piston M Schematic; labels, not drawing lengths, specify the data. (a) Linearize the pressure response to an outward displacement x and derive the effective spring constant and oscillation frequency. (b) Find the corresponding frequency if heat exchange were fast enough to keep the gas isothermal. Compare the two frequencies.
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Question 9 - Solution A confined gas acts as an adiabatic spring for a small piston motion gas x piston M (a) Method and calculation V = V0 + Ax, pV γ = p0V γ 0 ⇒δp ≃−γ p0A V0 x. Fnet = Aδp = −kgasx, kgas = γp0A2 V0 = 2800 N/m. fad = 1 2π √ kgas/M ≈5.95503 Hz. (b) Interpretation and further calculation kT = p0A2 V0 = 2000 N/m, fT = 1 2π √ kT /M ≈5.03292 Hz. fad/fT = √γ ≈1.18322. Adiabatic compression raises temperature and produces a stronger restoring pressure than isothermal compression. Physical check The linear approximation requires |Ax| ≪V0; thermal and acoustic time scales determine whether this model applies.

Question 9

A confined gas acts as an adiabatic spring for a small piston motion

An ideal gas at equilibrium pressure p0=100p_0=100 kPa and volume V0=.00500V_0=.00500 m3^3 supports a frictionless piston of area A=.0100A=.0100 m2^2 and moving mass M=2.00M=2.00 kg. External force is constant and balances the equilibrium pressure force. Small displacements are slow enough for uniform gas pressure but fast enough for negligible heat exchange. Take γ=1.40\gamma=1.40.

Diagram shown in the original SVG worksheet.

  1. Linearize the pressure response to an outward displacement xx and derive the effective spring constant and oscillation frequency.

  2. Find the corresponding frequency if heat exchange were fast enough to keep the gas isothermal. Compare the two frequencies.

Question 9 - Solution

A confined gas acts as an adiabatic spring for a small piston motion

Diagram shown in the original SVG worksheet.

(a) Method and calculation

V=V0+Ax,pVγ=p0V0γ⇒δp≃−γp0AV0x.V=V_0+Ax,\quad pV^\gamma=p_0V_0^\gamma\ \Rightarrow\ \delta p\simeq-\gamma\frac{p_0A}{V_0}x.Fnet=Aδp=−kgasx,kgas=γp0A2V0=2800N/m.F_{\mathrm{net}}=A\delta p=-k_{\mathrm{gas}}x,\quad k_{\mathrm{gas}}=\frac{\gamma p_0A^2}{V_0}=2800\,\mathrm{N/m}.fad=12πkgas/M≈5.95503Hz.f_{\mathrm{ad}}=\frac1{2\pi}\sqrt{k_{\mathrm{gas}}/M}\approx5.95503\,\mathrm{Hz}.

(b) Interpretation and further calculation

kT=p0A2V0=2000N/m,fT=12πkT/M≈5.03292Hz.k_T=\frac{p_0A^2}{V_0}=2000\,\mathrm{N/m},\quad f_T=\frac1{2\pi}\sqrt{k_T/M}\approx5.03292\,\mathrm{Hz}.fad/fT=γ≈1.18322.f_{\mathrm{ad}}/f_T=\sqrt\gamma\approx1.18322.Adiabatic compression raises temperature and produces a stronger restoring pressure than isothermal compression.

Physical check

The linear approximation requires |Ax|≪V0|Ax|\ll V_0; thermal and acoustic time scales determine whether this model applies.