Avogadro's Number — Question 6

Section 19-1 · Physics pages 3042–3043

Question 6 Dilution controls an expected count rather than a guaranteed integer Use NA = 6.02214076 × 1023 mol−1, exact. A solution contains solute at 1.00 × 10−9 mol/L. A well-mixed 1.00 µL aliquot is diluted by an overall concentration factor of 108 before a new 1.00 µL aliquot is taken from the final solution. Assume ideal uniform mixing and unchanged solute entities. stock diluted aliquot Schematic; labels, not drawing lengths, specify the data. (a) Find the expected solute count in a 1.00 microlitre sample before and after dilution. (b) For an independently supplied Poisson sampling model P(N = 0) = e−µ, find the empty-aliquot probability after dilution. What dilution factor would make the expected count exactly one?
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Question 6 - Solution Dilution controls an expected count rather than a guaranteed integer stock diluted aliquot (a) Method and calculation 1.00 µL = 10−6 L, µ0 = cV NA = 6.02214076 × 108. µ = µ0/108 = 6.02214076. (b) Interpretation and further calculation P(0) = e−6.02214076 ≈.00242447 (0.242447%). Dµ=1 = µ0 = 6.02214076 × 108. The expected count may be noninteger although every actual sample contains an integer number of solute entities. Physical check A mean of one does not mean exactly one in every aliquot; the sampling model must be stated separately.

Question 6

Dilution controls an expected count rather than a guaranteed integer

Use NA=6.02214076×1023mol−1N_A=6.02214076\times10^{23}\,\mathrm{mol^{-1}}, exact. A solution contains solute at 1.00×10−91.00\times10^{-9} mol/L. A well-mixed 1.00μ1.00\,\muL aliquot is diluted by an overall concentration factor of 10810^8 before a new 1.00μ1.00\,\muL aliquot is taken from the final solution. Assume ideal uniform mixing and unchanged solute entities.

Diagram shown in the original SVG worksheet.

  1. Find the expected solute count in a 1.00 microlitre sample before and after dilution.

  2. For an independently supplied Poisson sampling model P(N=0)=e−μP(N=0)=e^{-\mu}, find the empty-aliquot probability after dilution. What dilution factor would make the expected count exactly one?

Question 6 - Solution

Dilution controls an expected count rather than a guaranteed integer

Diagram shown in the original SVG worksheet.

(a) Method and calculation

1.00μL=10−6L,μ0=cVNA=6.02214076×108.1.00\,\mu\mathrm L=10^{-6}\,\mathrm L,\quad\mu_0=cVN_A=6.02214076\times10^8.μ=μ0/108=6.02214076.\mu=\mu_0/10^8=6.02214076.

(b) Interpretation and further calculation

P(0)=e−6.02214076≈.00242447(0.242447%).P(0)=e^{-6.02214076}\approx.00242447\quad(0.242447\%).Dμ=1=μ0=6.02214076×108.D_{\mu=1}=\mu_0=6.02214076\times10^8.The expected count may be noninteger although every actual sample contains an integer number of solute entities.

Physical check

A mean of one does not mean exactly one in every aliquot; the sampling model must be stated separately.