Temperature and Heat — Question 5

Section 18-6 · Physics pages 2920–2921

Question 5 A contact feels colder because it transfers energy faster A simplified contact model takes skin at 305 K and a surface at 295 K, both maintained at those temperatures. The heat-transfer rate is P = G(Tskin −Tsurface). Material M has GM = 4.0 W/K; material W has GW = .25 W/K. Contact lasts 2.0 s. skin surface G Schematic; labels, not drawing lengths, specify the data. (a) Find the outward skin heat for each material and their ratio. (b) If both surfaces are instead at 310 K, find the signed heat into the skin over 2.0 s. What can a stronger thermal sensation establish about temperature?
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Question 5 - Solution A contact feels colder because it transfers energy faster skin surface G (a) Method and calculation PM = 4(10) = 40 W, PW = .25(10) = 2.5 W. QM,out = 80 J, QW,out = 5.0 J, QM/QW = 16. (b) Interpretation and further calculation Qskin = G(Tsurface −Tskin)∆t. QM,skin = 40 J, QW,skin = 2.5 J. The direction reverses for a hotter surface. Magnitude also depends on conductance, so stronger sensation alone is not a temperature ranking. Physical check This maintained-temperature model neglects contact cooling and biological response; it isolates the transfer-rate distinction.

Question 5

A contact feels colder because it transfers energy faster

A simplified contact model takes skin at 305 K and a surface at 295 K, both maintained at those temperatures. The heat-transfer rate is P=G(Tskin−Tsurface)P=G(T_{\mathrm{skin}}-T_{\mathrm{surface}}). Material M has GM=4.0W/KG_M=4.0\,\mathrm{W/K}; material W has GW=.25W/KG_W=.25\,\mathrm{W/K}. Contact lasts 2.0 s.

Diagram shown in the original SVG worksheet.

  1. Find the outward skin heat for each material and their ratio.

  2. If both surfaces are instead at 310 K, find the signed heat into the skin over 2.0 s. What can a stronger thermal sensation establish about temperature?

Question 5 - Solution

A contact feels colder because it transfers energy faster

Diagram shown in the original SVG worksheet.

(a) Method and calculation

PM=4(10)=40W,PW=.25(10)=2.5W.P_M=4(10)=40\,\mathrm W,\quad P_W=.25(10)=2.5\,\mathrm W.QM,out=80J,QW,out=5.0J,QM/QW=16.Q_{M,\mathrm{out}}=80\,\mathrm J,\quad Q_{W,\mathrm{out}}=5.0\,\mathrm J,\quad Q_M/Q_W=16.

(b) Interpretation and further calculation

Qskin=G(Tsurface−Tskin)Δt.Q_{\mathrm{skin}}=G(T_{\mathrm{surface}}-T_{\mathrm{skin}})\Delta t.QM,skin=40J,QW,skin=2.5J.Q_{M,\mathrm{skin}}=40\,\mathrm J,\quad Q_{W,\mathrm{skin}}=2.5\,\mathrm J.The direction reverses for a hotter surface. Magnitude also depends on conductance, so stronger sensation alone is not a temperature ranking.

Physical check

This maintained-temperature model neglects contact cooling and biological response; it isolates the transfer-rate distinction.