Thermal Expansion — Question 4

Section 18-5 · Physics pages 2898–2899

Question 4 An overflowing liquid competes with its expanding container A vessel is filled exactly to its brim with V0 = 1.000 L of liquid. The liquid has volume coefficient βl = 9.00 × 10−4 K−1; the vessel is isotropic with linear coefficient αv = 1.00 × 10−5 K−1. Heat both uniformly by 50.0 K. Use first-order volume laws, with vessel coefficient βv = 3αv. liquid spill Schematic; labels, not drawing lengths, specify the data. (a) Find the volume overflowing, expressed at the final temperature. Compare with a calculation that treats the vessel as rigid. (b) If the initial fill is only .9700 L in the same vessel, determine whether overflow occurs and calculate the final empty volume or spill.
Show solutionHide solution
Question 4 - Solution An overflowing liquid competes with its expanding container liquid spill (a) Method and calculation Vl = V0(1 + βl∆T) = 1.0450 L, Vv = 1.0015 L. Vspill = Vl −Vv = .0435 L = 43.5 mL. A rigid-vessel estimate gives 45.0 mL and overestimates by 1.5 mL. (b) Interpretation and further calculation Vl = .9700(1.0450) = 1.01365 L. Vl −Vv = 1.01365 −1.00150 = .01215 L. There is still overflow, of 12.15 mL. The starting 30 mL headspace is smaller than the net volume gain. Physical check The spilled amount is a volume at the final temperature, not its equivalent volume after cooling.

Question 4

An overflowing liquid competes with its expanding container

A vessel is filled exactly to its brim with V0=1.000LV_0=1.000\,\mathrm L of liquid. The liquid has volume coefficient βl=9.00×10−4K−1\beta_l=9.00\times10^{-4}\,\mathrm{K^{-1}}; the vessel is isotropic with linear coefficient αv=1.00×10−5K−1\alpha_v=1.00\times10^{-5}\,\mathrm{K^{-1}}. Heat both uniformly by 50.0K50.0\,\mathrm K. Use first-order volume laws, with vessel coefficient βv=3αv\beta_v=3\alpha_v.

Diagram shown in the original SVG worksheet.

  1. Find the volume overflowing, expressed at the final temperature. Compare with a calculation that treats the vessel as rigid.

  2. If the initial fill is only .9700L.9700\,\mathrm L in the same vessel, determine whether overflow occurs and calculate the final empty volume or spill.

Question 4 - Solution

An overflowing liquid competes with its expanding container

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Vl=V0(1+βlΔT)=1.0450L,Vv=1.0015L.V_l=V_0(1+\beta_l\Delta T)=1.0450\,\mathrm L,\quad V_v=1.0015\,\mathrm L.Vspill=Vl−Vv=.0435L=43.5mL.V_{\mathrm{spill}}=V_l-V_v=.0435\,\mathrm L=43.5\,\mathrm{mL}.A rigid-vessel estimate gives 45.0 mL and overestimates by 1.5 mL.

(b) Interpretation and further calculation

Vl=.9700(1.0450)=1.01365L.V_l=.9700(1.0450)=1.01365\,\mathrm L.Vl−Vv=1.01365−1.00150=.01215L.V_l-V_v=1.01365-1.00150=.01215\,\mathrm L.There is still overflow, of 12.15 mL. The starting 30 mL headspace is smaller than the net volume gain.

Physical check

The spilled amount is a volume at the final temperature, not its equivalent volume after cooling.