Thermal Expansion — Question 1

Section 18-5 · Physics pages 2892–2893

Question 1 Two anchored rods close a shared clearance Two rods point toward each other across a 2.10 mm gap at 20◦C. Their outer ends are fixed, while their facing ends can expand freely until contact. Rod A has LA = 2.00 m, αA = 12.0 × 10−6 K−1; B has LB = 3.00 m, αB = 20.0 × 10−6 K−1. Use ∆L = αL∆T. g0 A B Outer ends anchored; the central gap is exaggerated. (a) Find the gap at 35◦C and the temperature of first contact. (b) At 60◦C, calculate the free-expansion overlap. Explain why it is not a physical negative gap and what additional model is needed.
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Question 1 - Solution Two anchored rods close a shared clearance g0 A B (a) Method and calculation g = g0 −(αALA + αBLB)∆T, αALA + αBLB = 84.0 µm/K. g(35) = 2.10 −.084(15) = .840 mm, ∆Tc = 2.10/.084 = 25.0 K. First contact occurs at 45.0◦C. (b) Interpretation and further calculation ∆Lfree = .084(40) = 3.36 mm, ∆Lfree −g0 = 1.26 mm. The formal gap is −1.26 mm, signaling failure of the free-expansion assumption. g ≥0 for noninterpenetrating rods. Elastic compression, support motion or instability must accommodate the excess expansion. Physical check Both inward tip motions reduce the same gap, so their free expansions add.

Question 1

Two anchored rods close a shared clearance

Two rods point toward each other across a 2.10mm2.10\,\mathrm{mm} gap at 20∘C20^\circ\mathrm C. Their outer ends are fixed, while their facing ends can expand freely until contact. Rod A has LA=2.00mL_A=2.00\,\mathrm m, αA=12.0×10−6K−1\alpha_A=12.0\times10^{-6}\,\mathrm{K^{-1}}; B has LB=3.00mL_B=3.00\,\mathrm m, αB=20.0×10−6K−1\alpha_B=20.0\times10^{-6}\,\mathrm{K^{-1}}. Use ΔL=αLΔT\Delta L=\alpha L\Delta T.

Diagram shown in the original SVG worksheet.

  1. Find the gap at 35∘C35^\circ\mathrm C and the temperature of first contact.

  2. At 60∘C60^\circ\mathrm C, calculate the free-expansion overlap. Explain why it is not a physical negative gap and what additional model is needed.

Question 1 - Solution

Two anchored rods close a shared clearance

Diagram shown in the original SVG worksheet.

(a) Method and calculation

g=g0−(αALA+αBLB)ΔT,αALA+αBLB=84.0μm/K.g=g_0-(\alpha_AL_A+\alpha_BL_B)\Delta T,\quad\alpha_AL_A+\alpha_BL_B=84.0\,\mu\mathrm{m/K}.g(35)=2.10−.084(15)=.840mm,ΔTc=2.10/.084=25.0K.g(35)=2.10-.084(15)=.840\,\mathrm{mm},\quad\Delta T_c=2.10/.084=25.0\,\mathrm K.First contact occurs at 45.0∘45.0^\circC.

(b) Interpretation and further calculation

ΔLfree=.084(40)=3.36mm,ΔLfree−g0=1.26mm.\Delta L_{\mathrm{free}}=.084(40)=3.36\,\mathrm{mm},\quad\Delta L_{\mathrm{free}}-g_0=1.26\,\mathrm{mm}.The formal gap is −1.26-1.26 mm, signaling failure of the free-expansion assumption.g≥0for noninterpenetrating rods.g\ge0\quad\text{for noninterpenetrating rods}.Elastic compression, support motion or instability must accommodate the excess expansion.

Physical check

Both inward tip motions reduce the same gap, so their free expansions add.