Supersonic Speeds, Shock Waves — Question 3

Section 17-9 · Physics pages 2796–2797

Question 3 A boom delay determines Mach number only within its allowed range For steady horizontal supersonic flight directly over an observer, the weak-cone model gives tb = (h/c) √ 1 −M−2. A known altitude is h = 1000 m, sound speed is 340 m/s, and boom delay after overhead passage is 2.00 s. O S h x Source position when the cone reaches the ground observer; geometry is schematic. (a) Infer Mach number and speed. (b) Determine the allowed range of positive delays under this model. Would a 3.20 s delay be compatible with the same altitude and sound speed?
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Question 3 - Solution A boom delay determines Mach number only within its allowed range O S h x (a) Method and calculation Let q = ctb/h = 0.680. Squaring and rearranging gives q2 = 1 −M−2, M = 1 √ 1 −q2 = 1.36386. v = Mc = 463.71 m/s. (b) Interpretation and further calculation For finite M > 1, 0 < √ 1 −M−2 < 1 ⇒0 < tb < h/c = 2.94118 s. A 3.20 s delay is incompatible with the stated steady, directly-overhead weak-cone model. It could not be repaired by choosing a larger Mach number; the delay approaches h/c from below as M →∞. Physical check The inferred Mach number is greater than one. Near-sonic limiting results assume an increasingly long prior flight history, an important condition of the steady model.

Question 3

A boom delay determines Mach number only within its allowed range

For steady horizontal supersonic flight directly over an observer, the weak-cone model gives tb=(h/c)1−M−2t_b=(h/c)\sqrt{1-M^{-2}}. A known altitude is h=1000mh=1000\,\mathrm m, sound speed is 340m/s340\,\mathrm{m/s}, and boom delay after overhead passage is 2.00s2.00\,\mathrm s.

Diagram shown in the original SVG worksheet.

  1. Infer Mach number and speed.

  2. Determine the allowed range of positive delays under this model. Would a 3.20s3.20\,\mathrm s delay be compatible with the same altitude and sound speed?

Question 3 - Solution

A boom delay determines Mach number only within its allowed range

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Let q=ctb/h=0.680q=ct_b/h=0.680. Squaring and rearranging givesq2=1−M−2,M=11−q2=1.36386.q^2=1-M^{-2},\quad M=\frac1{\sqrt{1-q^2}}=1.36386.v=Mc=463.71m/s.v=Mc=463.71\,\mathrm{m/s}.

(b) Interpretation and further calculation

For finite M>1M>1,0<1−M−2<1⇒0<tb<h/c=2.94118s.0<\sqrt{1-M^{-2}}<1\Rightarrow0<t_b<h/c=2.94118\,\mathrm s.A 3.20s3.20\,\mathrm s delay is incompatible with the stated steady, directly-overhead weak-cone model. It could not be repaired by choosing a larger Mach number; the delay approaches h/ch/c from below as M→∞M\to\infty.

Physical check

The inferred Mach number is greater than one. Near-sonic limiting results assume an increasingly long prior flight history, an important condition of the steady model.