Traveling Sound Waves — Question 10

Section 17-3 · Physics pages 2690–2691

Question 10 Three smallness tests reduce to the same acoustic parameter A progressive plane wave has displacement amplitude a, wave number k, pressure amplitude P, and particle speed amplitude um. Use P = Bka, um = ωa, c = ω/k and B = ρ0c2. Take P = 140 Pa and B = 1.4 × 105 Pa. x ξ Displacement amplitude must be compared with wavelength to assess strain. (a) Show that strain, pressure fraction and particle Mach number coincide in magnitude. (b) Find the maximum allowed pressure amplitude if each parameter must be below 0.01. Explain why small displacement alone is not an adequate criterion.
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Question 10 - Solution Three smallness tests reduce to the same acoustic parameter x ξ (a) Method and calculation Eliminate the dimensional amplitude: ka = P B , um c = ωa ω/k = ka. ϵ ≡ka = P B = um c = 10−3. The given wave satisfies a one-percent small-perturbation threshold. (b) Interpretation and further calculation The strict criterion ϵ < 0.01 requires P < 0.01B = 1400 Pa. The same microscopic displacement can produce a much larger strain if wavelength is shorter: ka = 2πa/λ. Smallness must be assessed against a relevant length or pressure scale, not from the numerical value of a alone. Physical check These equalities refer to a single progressive linear plane wave. They do not replace a nonlinear propagation model once the perturbation becomes large.

Question 10

Three smallness tests reduce to the same acoustic parameter

A progressive plane wave has displacement amplitude aa, wave number kk, pressure amplitude PP, and particle speed amplitude umu_m. Use P=BkaP=Bka, um=ωau_m=\omega a, c=ω/kc=\omega/k and B=ρ0c2B=\rho_0c^2. Take P=140PaP=140\,\mathrm{Pa} and B=1.4×105PaB=1.4\times10^5\,\mathrm{Pa}.

Diagram shown in the original SVG worksheet.

  1. Show that strain, pressure fraction and particle Mach number coincide in magnitude.

  2. Find the maximum allowed pressure amplitude if each parameter must be below 0.010.01. Explain why small displacement alone is not an adequate criterion.

Question 10 - Solution

Three smallness tests reduce to the same acoustic parameter

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Eliminate the dimensional amplitude:ka=PB,umc=ωaω/k=ka.ka=\frac PB,\qquad\frac{u_m}{c}=\frac{\omega a}{\omega/k}=ka.ϵ≡ka=PB=umc=10−3.\epsilon\equiv ka=\frac PB=\frac{u_m}{c}=10^{-3}.The given wave satisfies a one-percent small-perturbation threshold.

(b) Interpretation and further calculation

The strict criterion ϵ<0.01\epsilon<0.01 requiresP<0.01B=1400Pa.P<0.01B=1400\,\mathrm{Pa}.The same microscopic displacement can produce a much larger strain if wavelength is shorter: ka=2πa/λka=2\pi a/\lambda. Smallness must be assessed against a relevant length or pressure scale, not from the numerical value of aa alone.

Physical check

These equalities refer to a single progressive linear plane wave. They do not replace a nonlinear propagation model once the perturbation becomes large.