The Principle of Superposition for Waves — Question 9

Section 16-8 · Physics pages 2548–2549

Question 9 A nonlinear restoring term prevents unrestricted superposition Consider the model ytt −v2yxx + γy2 = 0, with γ̸ = 0. Two functions y1, y2 each solve it separately. x q A sum of two profiles need not satisfy a nonlinear restoring law. (a) Find the residual obtained by substituting y1 + y2. (b) State when this residual vanishes and explain why small amplitude can make superposition an approximation rather than an exact rule.
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Question 9 - Solution A nonlinear restoring term prevents unrestricted superposition x q Method and mathematical working Substitute the sum into the full nonlinear equation. The individual residuals vanish, leaving the mixed term from the square. γ(y1 + y2)2 = γy2 1 + γy2 2 + 2γy1y2, N[y1 + y2] = 2γy1y2. y1, y2 = O(ϵ) ⇒2γy1y2 = O(ϵ2), ϵ →0 : linear limit. (a) Calculation and conclusion The linear derivative terms add, but γ(y1 + y2)2 includes 2γy1y2. Subtracting the two individual equations leaves residual 2γy1y2. (b) Interpretation and limits The residual vanishes where one field is zero, or in special cases with zero product. In general overlap it is nonzero. Scaling both amplitudes by a small factor makes the nonlinear residual quadratic in that factor, compared with linear terms, allowing a controlled leading-order approximation when the model scales justify it. Physical check The residual is second order in small displacement amplitudes. Neglecting it can justify an approximate linear theory, but exact superposition requires the nonlinear coupling to vanish.

Question 9

A nonlinear restoring term prevents unrestricted superposition

Consider the model ytt−v2yxx+γy2=0y_{tt}-v^2y_{xx}+\gamma y^2=0, with γ≠0\gamma\ne0. Two functions y1,y2y_1,y_2 each solve it separately.

Diagram shown in the original SVG worksheet.

  1. Find the residual obtained by substituting y1+y2y_1+y_2.

  2. State when this residual vanishes and explain why small amplitude can make superposition an approximation rather than an exact rule.

Question 9 - Solution

A nonlinear restoring term prevents unrestricted superposition

Diagram shown in the original SVG worksheet.

Method and mathematical working

Substitute the sum into the full nonlinear equation. The individual residuals vanish, leaving the mixed term from the square.γ(y1+y2)2=γy12+γy22+2γy1y2,𝒩[y1+y2]=2γy1y2.y1,y2=O(ϵ)⇒2γy1y2=O(ϵ2),ϵ→0:linear limit.\begin{aligned}\gamma(y_1+y_2)^2&=\gamma y_1^2+\gamma y_2^2+2\gamma y_1y_2,\\\mathcal N[y_1+y_2]&=2\gamma y_1y_2.\\[4pt]y_1,y_2=O(\epsilon)&\Rightarrow2\gamma y_1y_2=O(\epsilon^2),\qquad\epsilon\to0:\ \text{linear limit}.\end{aligned}

(a) Calculation and conclusion

The linear derivative terms add, but γ(y1+y2)2\gamma(y_1+y_2)^2 includes 2γy1y22\gamma y_1y_2. Subtracting the two individual equations leaves residual 2γy1y22\gamma y_1y_2.

(b) Interpretation and limits

The residual vanishes where one field is zero, or in special cases with zero product. In general overlap it is nonzero. Scaling both amplitudes by a small factor makes the nonlinear residual quadratic in that factor, compared with linear terms, allowing a controlled leading-order approximation when the model scales justify it.

Physical check

The residual is second order in small displacement amplitudes. Neglecting it can justify an approximate linear theory, but exact superposition requires the nonlinear coupling to vanish.