The Principle of Superposition for Waves — Question 5

Section 16-8 · Physics pages 2540–2541

Question 5 A fixed endpoint requires an inverted reflected pulse A string occupies x < 0 and is fixed at x = 0. An incident pulse traveling right is yi = f(x −vt). Seek a leftward reflection in terms of the same function. incident fixed x = 0 An incident pulse approaches a rigid endpoint from the left. (a) Construct a reflected field that enforces y(0, t) = 0 for every time. (b) Find the endpoint slope and power. Does a nonzero force on the support imply energy transfer into an immobile support?
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Question 5 - Solution A fixed endpoint requires an inverted reflected pulse incident fixed x = 0 Method and mathematical working Construct the reflected argument so that both profiles sample the same value at the boundary. Choose its sign to enforce zero endpoint displacement for every time. y(0, t) = f(−vt) −f(−vt) = 0, yx(0, t) = 2f′(−vt), yt(0, t) = 0. yr = −f(−x −vt), P(0, t) = −Fyx(0, t) yt(0, t) | {z } 0 = 0. (a) Calculation and conclusion Choose yr = −f(−x −vt). At zero, incident and reflected displacements cancel exactly. The reflected pulse is inverted in displacement and moves toward decreasing x. (b) Interpretation and limits Total slope at the endpoint is 2f′(−vt), so a transverse force can be present. But endpoint velocity is zero, and P = −Fyxyt = 0. A stationary ideal support can exchange momentum through force without doing mechanical work. Physical check The endpoint can sustain a transverse force but has zero velocity. Their product, the boundary power, is therefore zero despite the nonzero boundary slope.

Question 5

A fixed endpoint requires an inverted reflected pulse

A string occupies x<0x<0 and is fixed at x=0x=0. An incident pulse traveling right is yi=f(x−vt)y_i=f(x-vt). Seek a leftward reflection in terms of the same function.

Diagram shown in the original SVG worksheet.

  1. Construct a reflected field that enforces y(0,t)=0y(0,t)=0 for every time.

  2. Find the endpoint slope and power. Does a nonzero force on the support imply energy transfer into an immobile support?

Question 5 - Solution

A fixed endpoint requires an inverted reflected pulse

Diagram shown in the original SVG worksheet.

Method and mathematical working

Construct the reflected argument so that both profiles sample the same value at the boundary. Choose its sign to enforce zero endpoint displacement for every time.y(0,t)=f(−vt)−f(−vt)=0,yx(0,t)=2f′(−vt),yt(0,t)=0.yr=−f(−x−vt),P(0,t)=−Fyx(0,t)yt(0,t)⏟0=0.\begin{aligned}y(0,t)&=f(-vt)-f(-vt)=0,\\y_x(0,t)&=2f^{\prime}(-vt),\qquad y_t(0,t)=0.\\[4pt]y_r&=-f(-x-vt),\qquad P(0,t)=-Fy_x(0,t)\underbrace{y_t(0,t)}_{0}=0.\end{aligned}

(a) Calculation and conclusion

Choose yr=−f(−x−vt)y_r=-f(-x-vt). At zero, incident and reflected displacements cancel exactly. The reflected pulse is inverted in displacement and moves toward decreasing xx.

(b) Interpretation and limits

Total slope at the endpoint is 2f′(−vt)2f^{\prime}(-vt), so a transverse force can be present. But endpoint velocity is zero, and P=−Fyxyt=0P=-Fy_xy_t=0. A stationary ideal support can exchange momentum through force without doing mechanical work.

Physical check

The endpoint can sustain a transverse force but has zero velocity. Their product, the boundary power, is therefore zero despite the nonzero boundary slope.