The Principle of Superposition for Waves — Question 1

Section 16-8 · Physics pages 2532–2533

Question 1 Linearity applies to displacement before it applies to any energy calculation Two solutions y1, y2 satisfy ytt = v2yxx on the same uniform string. Let y = ay1 + by2, where a, b are constants. x q A linear combination of two allowed profiles is another candidate solution. (a) Prove that y satisfies the same equation. (b) Why does this proof not establish that the energy density equals a2u1 + b2u2 at every point?
Show solutionHide solution
Question 1 - Solution Linearity applies to displacement before it applies to any energy calculation x q Method and mathematical working Apply the linear differential operator separately to each term in the proposed combination. Then expand the quadratic energy to see why a different rule applies to energy. L[ay1 + by2] = aL[y1] + bL[y2] = 0, u[y1 + y2] = u[y1] + u[y2] + µy1ty2t + Fy1xy2x. (ay1 + by2)tt −v2(ay1 + by2)xx = a(0) + b(0) = 0. (a) Calculation and conclusion Linear differentiation gives ytt −v2yxx = a(y1,tt −v2y1,xx) + b(y2,tt −v2y2,xx) = 0. Both fields must obey the same equation and domain assumptions. (b) Interpretation and limits Energy contains squared derivatives. Expanding gives cross terms ab[µy1,ty2,t + Fy1,xy2,x], which need not vanish locally. Superposition is a statement about the displacement equation, not automatic addition of every quadratic observable. Physical check Superposition of displacement follows from a linear equation of motion. Additivity of energy requires the cross terms to vanish or cancel after the appropriate integration; it is a separate question.

Question 1

Linearity applies to displacement before it applies to any energy calculation

Two solutions y1,y2y_1,y_2 satisfy ytt=v2yxxy_{tt}=v^2y_{xx} on the same uniform string. Let y=ay1+by2y=ay_1+by_2, where a,ba,b are constants.

Diagram shown in the original SVG worksheet.

  1. Prove that yy satisfies the same equation.

  2. Why does this proof not establish that the energy density equals a2u1+b2u2a^2u_1+b^2u_2 at every point?

Question 1 - Solution

Linearity applies to displacement before it applies to any energy calculation

Diagram shown in the original SVG worksheet.

Method and mathematical working

Apply the linear differential operator separately to each term in the proposed combination. Then expand the quadratic energy to see why a different rule applies to energy.ℒ[ay1+by2]=aℒ[y1]+bℒ[y2]=0,u[y1+y2]=u[y1]+u[y2]+μy1ty2t+Fy1xy2x.(ay1+by2)tt−v2(ay1+by2)xx=a(0)+b(0)=0.\begin{aligned}\mathcal L[ay_1+by_2]&=a\mathcal L[y_1]+b\mathcal L[y_2]=0,\\u[y_1+y_2]&=u[y_1]+u[y_2]+\mu y_{1t}y_{2t}+F y_{1x}y_{2x}.\\[4pt](ay_1+by_2)_{tt}-v^2(ay_1+by_2)_{xx}&=a(0)+b(0)=0.\end{aligned}

(a) Calculation and conclusion

Linear differentiation gives ytt−v2yxx=a(y1,tt−v2y1,xx)+b(y2,tt−v2y2,xx)=0y_{tt}-v^2y_{xx}=a(y_{1,tt}-v^2y_{1,xx})+b(y_{2,tt}-v^2y_{2,xx})=0. Both fields must obey the same equation and domain assumptions.

(b) Interpretation and limits

Energy contains squared derivatives. Expanding gives cross terms ab[μy1,ty2,t+Fy1,xy2,x]ab[\mu y_{1,t}y_{2,t}+F y_{1,x}y_{2,x}], which need not vanish locally. Superposition is a statement about the displacement equation, not automatic addition of every quadratic observable.

Physical check

Superposition of displacement follows from a linear equation of motion. Additivity of energy requires the cross terms to vanish or cancel after the appropriate integration; it is a separate question.