Energy and Power of a Wave Traveling Along a String — Question 3

Section 16-6 · Physics pages 2496–2497

Question 3 A fixed power budget fixes particle velocity amplitude on one string On the same uniform string, two sinusoidal waves are generated separately with equal mean powers. The second has frequency three times the first. F1 frequency f, amplitude A F2 frequency 3f, equal mean power Separate string configurations; labels identify the controlled quantities. (a) Compare displacement amplitudes and maximum transverse velocities. (b) Compare wavelengths and maximum slopes. State the assumptions behind the cancellation.
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Question 3 - Solution A fixed power budget fixes particle velocity amplitude on one string F1 frequency f, amplitude A F2 frequency 3f, equal mean power Method and mathematical working With the string properties fixed, equal power fixes the product Aω. Track wavelength and slope using the same unchanged wave speed. P = 1 2µv(Aω)2, A2ω2 = A1ω1, kA = ωA v . ω2 = 3ω1 ⇒A2 = A1/3, λ2 = λ1/3, A2k2 = A1k1. (a) Calculation and conclusion Since P ∝ω2A2 at fixed µ, v, A2 = A1/3. Consequently ω2A2 = ω1A1, so the maximum transverse velocities are equal. (b) Interpretation and limits λ2 = λ1/3 and k2 = 3k1. Therefore k2A2 = k1A1, so the maximum slopes are equal as well. The result assumes a nondispersive linear string with unchanged tension, density and traveling-wave character. Physical check The smaller displacement amplitude does not imply smaller material velocity: the oscillation is faster by exactly the compensating factor. The maximum slope also remains unchanged.

Question 3

A fixed power budget fixes particle velocity amplitude on one string

On the same uniform string, two sinusoidal waves are generated separately with equal mean powers. The second has frequency three times the first.

Diagram shown in the original SVG worksheet.

  1. Compare displacement amplitudes and maximum transverse velocities.

  2. Compare wavelengths and maximum slopes. State the assumptions behind the cancellation.

Question 3 - Solution

A fixed power budget fixes particle velocity amplitude on one string

Diagram shown in the original SVG worksheet.

Method and mathematical working

With the string properties fixed, equal power fixes the product AωA\omega. Track wavelength and slope using the same unchanged wave speed.P¯=12μv(Aω)2,A2ω2=A1ω1,kA=ωAv.ω2=3ω1⇒A2=A1/3,λ2=λ1/3,A2k2=A1k1.\begin{aligned}\overline P&=\tfrac12\mu v(A\omega)^2,\\A_2\omega_2&=A_1\omega_1,\qquad kA=\frac{\omega A}{v}.\\[4pt]\omega_2=3\omega_1&\Rightarrow A_2=A_1/3,\quad\lambda_2=\lambda_1/3,\quad A_2k_2=A_1k_1.\end{aligned}

(a) Calculation and conclusion

Since P¯∝ω2A2\overline P\propto\omega^2A^2 at fixed μ,v\mu,v, A2=A1/3A_2=A_1/3. Consequently ω2A2=ω1A1\omega_2A_2=\omega_1A_1, so the maximum transverse velocities are equal.

(b) Interpretation and limits

λ2=λ1/3\lambda_2=\lambda_1/3 and k2=3k1k_2=3k_1. Therefore k2A2=k1A1k_2A_2=k_1A_1, so the maximum slopes are equal as well. The result assumes a nondispersive linear string with unchanged tension, density and traveling-wave character.

Physical check

The smaller displacement amplitude does not imply smaller material velocity: the oscillation is faster by exactly the compensating factor. The maximum slope also remains unchanged.