Phasors — Question 8

Section 16-10 · Physics pages 2586–2587

Question 8 Phase unwrapping restores a continuous spatial advance Three equally spaced sensors report phases 170◦, −175◦, −160◦using the interval (−180◦, 180◦]. The separation is d = .020 m. Independent information says phase increases by less than 180◦per sensor step. sensor 1 170◦ sensor 2 −175◦ sensor 3 −160◦ Equally spaced sensors report wrapped phases; the stated positive-increment bound selects the unwrapping. (a) Unwrap the phases and infer wavelength. (b) Explain what ambiguity would remain without the independent advance bound.
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Question 8 - Solution Phase unwrapping restores a continuous spatial advance sensor 1 170◦ sensor 2 −175◦ sensor 3 −160◦ Method and mathematical working Add complete turns to preserve the specified positive, sub-180◦increment between adjacent sensors. Then convert the unwrapped increment to a spatial gradient. 170◦, −175◦, −160◦−→170◦, 185◦, 200◦, kd = 15◦= π 12, λ = 2πd π/12. k = π/12 0.020 = 25π 6 rad/m, λ = 2π k = 0.480 m. (a) Calculation and conclusion Continuous phases can be 170◦, 185◦, 200◦, so each step advances 15◦. Thus d/λ = 15/360, giving λ = 24d = .480 m. (b) Interpretation and limits Additional full 360◦advances could occur between sensors while leaving the reported principal phases unchanged. The positive-advance bound chooses the small increment. A numerical discontinuity at the reporting branch cut does not represent a physical jump in the wave. Physical check Both neighboring intervals independently give the same phase advance. Without the increment bound, additional whole turns could be inserted and the wavelength would not be uniquely determined.

Question 8

Phase unwrapping restores a continuous spatial advance

Three equally spaced sensors report phases 170∘,−175∘,−160∘170^\circ,-175^\circ,-160^\circ using the interval (−180∘,180∘](-180^\circ,180^\circ]. The separation is d=.020md=.020\,\mathrm{m}. Independent information says phase increases by less than 180∘180^\circ per sensor step.

Diagram shown in the original SVG worksheet.

  1. Unwrap the phases and infer wavelength.

  2. Explain what ambiguity would remain without the independent advance bound.

Question 8 - Solution

Phase unwrapping restores a continuous spatial advance

Diagram shown in the original SVG worksheet.

Method and mathematical working

Add complete turns to preserve the specified positive, sub-180∘180^\circ increment between adjacent sensors. Then convert the unwrapped increment to a spatial gradient.170∘,−175∘,−160∘→170∘,185∘,200∘,kd=15∘=π12,λ=2πdπ/12.k=π/120.020=25π6rad/m,λ=2πk=0.480m.\begin{aligned}170^\circ,\,-175^\circ,\,-160^\circ&\longrightarrow170^\circ,185^\circ,200^\circ,\\kd&=15^\circ=\frac\pi{12},\qquad \lambda=\frac{2\pi d}{\pi/12}.\\[4pt]k&=\frac{\pi/12}{0.020}=\frac{25\pi}{6}\,\mathrm{rad/m},\qquad\lambda=\frac{2\pi}{k}=0.480\,\mathrm m.\end{aligned}

(a) Calculation and conclusion

Continuous phases can be 170∘,185∘,200∘170^\circ,185^\circ,200^\circ, so each step advances 15∘15^\circ. Thus d/λ=15/360d/\lambda=15/360, giving λ=24d=.480m\lambda=24d=.480\,\mathrm{m}.

(b) Interpretation and limits

Additional full 360∘360^\circ advances could occur between sensors while leaving the reported principal phases unchanged. The positive-advance bound chooses the small increment. A numerical discontinuity at the reporting branch cut does not represent a physical jump in the wave.

Physical check

Both neighboring intervals independently give the same phase advance. Without the increment bound, additional whole turns could be inserted and the wavelength would not be uniquely determined.