Ideal Fluids in Motion — Question 7

Section 14-7 · Physics pages 2184–2185

Question 7 An ideal wall forbids penetration but can allow tangential slip A stationary straight wall lies along y = 0, with fluid in y > 0. Candidate velocity fields near it are A: (U, 0), B: (U, V ) with V̸ = 0, and C: (ay, 0). Take all constants finite. An inviscid model imposes no normal flow through the wall; a viscous no-slip model additionally matches the wall's tangential velocity. vx y fluid A stationary impermeable wall; tangential slip is a separate condition. (a) Which fields satisfy impermeability? Which satisfy no slip at the wall? (b) Why is field A permissible in an ideal inviscid calculation even though a real stationary wall often has nearly zero adjacent fluid velocity?
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Question 7 - Solution An ideal wall forbids penetration but can allow tangential slip vx y fluid (a) Derivation and calculation At the stationary wall, impermeability requires vy(x, 0) = 0: A : (U, 0) ✓, B : (U, V ) fails, C : (0, 0) ✓. impermeability: A and C . No slip additionally requires vx(x, 0) = 0, giving no slip: C only . (b) Result and interpretation For an ideal impermeable wall, v · ˆn = 0 does not require v · ˆt = 0. An inviscid outer model can permit tangential slip. Real viscous flow can adjust near the wall; accuracy depends on the observable and on whether that near-wall region matters. Physical check Field B crosses a solid wall and fails even the weaker inviscid boundary condition.

Question 7

An ideal wall forbids penetration but can allow tangential slip

A stationary straight wall lies along y=0y=0, with fluid in y>0y>0. Candidate velocity fields near it are A: (U,0)(U,0), B: (U,V)(U,V) with V≠0V\ne0, and C: (ay,0)(ay,0). Take all constants finite. An inviscid model imposes no normal flow through the wall; a viscous no-slip model additionally matches the wall's tangential velocity.

Diagram shown in the original SVG worksheet.

  1. Which fields satisfy impermeability? Which satisfy no slip at the wall?

  2. Why is field A permissible in an ideal inviscid calculation even though a real stationary wall often has nearly zero adjacent fluid velocity?

Question 7 - Solution

An ideal wall forbids penetration but can allow tangential slip

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

At the stationary wall, impermeability requires vy(x,0)=0v_y(x,0)=0:A:(U,0)✓,B:(U,V)fails,C:(0,0)✓.A:(U,0)\ \checkmark,\qquad B:(U,V)\ \text{fails},\qquad C:(0,0)\ \checkmark.impermeability: A and C.\boxed{\text{impermeability: A and C}}.No slip additionally requires vx(x,0)=0v_x(x,0)=0, givingno slip: C only.\boxed{\text{no slip: C only}}.

(b) Result and interpretation

For an ideal impermeable wall,𝒗⋅𝒏̂=0\mathbf v\cdot\hat{\mathbf n}=0does not require𝒗⋅𝒕̂=0.\text{does not require}\quad\mathbf v\cdot\hat{\mathbf t}=0.An inviscid outer model can permit tangential slip. Real viscous flow can adjust near the wall; accuracy depends on the observable and on whether that near-wall region matters.

Physical check

Field B crosses a solid wall and fails even the weaker inviscid boundary condition.