Ideal Fluids in Motion — Question 3

Section 14-7 · Physics pages 2176–2177

Question 3 An instantaneous streamline can differ from a particle path A spatially uniform but time-dependent flow is v = Uˆi + btˆj, with U > 0 and b > 0. A marked parcel starts at the origin at t = 0. A streamline is everywhere tangent to the velocity field at one chosen instant. x y path Schematic parabola and one straight instantaneous streamline through the origin. (a) Find the streamline through the origin at time t0 and the marked parcel path. (b) Compare their slopes when the parcel is at time t0 > 0. Why can the path and a streamline be tangent locally without being the same curve?
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Question 3 - Solution An instantaneous streamline can differ from a particle path x y path (a) Derivation and calculation At the chosen instant t0, dy dx = bt0 U ⇒ystreamline = bt0 U x through the origin. ˙x = U, ˙y = bt ⇒x = Ut, y = 1 2bt2. ypath = b 2U2 x2 . (b) Result and interpretation At the parcel position x0 = Ut0, dypath dx x0 = bx0 U2 = bt0 U . y −1 2bt2 0 = bt0 U (x −Ut0) is the instantaneous streamline through the parcel. It is locally tangent to the path, but is not generally the streamline through the origin or the full path history. Physical check For t0 > 0, the origin streamline and the parcel tangent line are parallel with different intercepts.

Question 3

An instantaneous streamline can differ from a particle path

A spatially uniform but time-dependent flow is 𝒗=Uî+btĵ\mathbf v=U\hat i+bt\hat j, with U>0U>0 and b>0b>0. A marked parcel starts at the origin at t=0t=0. A streamline is everywhere tangent to the velocity field at one chosen instant.

Diagram shown in the original SVG worksheet.

  1. Find the streamline through the origin at time t0t_0 and the marked parcel path.

  2. Compare their slopes when the parcel is at time t0>0t_0>0. Why can the path and a streamline be tangent locally without being the same curve?

Question 3 - Solution

An instantaneous streamline can differ from a particle path

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

At the chosen instant t0t_0,dydx=bt0U⇒ystreamline=bt0Uxthrough the origin.\frac{dy}{dx}=\frac{bt_0}{U}\Rightarrow\boxed{y_{\mathrm{streamline}}=\frac{bt_0}{U}x}\quad\text{through the origin}.ẋ=U,ẏ=bt⇒x=Ut,y=12bt2.\dot x=U,\quad\dot y=bt\Rightarrow x=Ut,\quad y=\tfrac12bt^2.ypath=b2U2x2.\boxed{y_{\mathrm{path}}=\frac{b}{2U^2}x^2}.

(b) Result and interpretation

At the parcel position x0=Ut0x_0=Ut_0,dypathdx|x0=bx0U2=bt0U.\left.\frac{dy_{\mathrm{path}}}{dx}\right|_{x_0}=\frac{bx_0}{U^2}=\frac{bt_0}{U}.y−12bt02=bt0U(x−Ut0)y-\tfrac12bt_0^2=\frac{bt_0}{U}(x-Ut_0)is the instantaneous streamline through the parcel.\text{is the instantaneous streamline through the parcel}.It is locally tangent to the path, but is not generally the streamline through the origin or the full path history.

Physical check

For t0>0t_0>0, the origin streamline and the parcel tangent line are parallel with different intercepts.