Pascal's Principle — Question 7

Section 14-5 · Physics pages 2144–2145

Question 7 A trapped bubble consumes stroke before useful motion A hydraulic line contains a trapped gas bubble of volume V0 = 2.0 cm3 at absolute pressure p0 = 100 kPa. The rest of the liquid is incompressible. Before the output can move, line pressure must reach 500 kPa absolute. A master piston of area Am = 1.0 cm2 supplies the volume change. Assume isothermal bubble compression, pV = constant. gas A trapped gas bubble shrinks as line pressure rises, consuming input stroke before the output moves. (a) Find the input travel needed solely to compress the bubble to the lifting threshold. (b) At that threshold, does the bubble prevent static pressure transmission? Explain the distinction between force transmission and displacement response.
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Question 7 - Solution A trapped bubble consumes stroke before useful motion gas (a) Derivation and calculation p0V0 = pfVf ⇒Vf = 100 500(2.0) = .400 cm3 . ∆V = V0 −Vf = 1.60 cm3. xm = ∆V/Am = 1.60/1.0 = 1.60 cm . (b) Result and interpretation At static equilibrium, gas and liquid share the local pressure. The volume-pressure response is V (p) = p0V0/p, −dV dp = p0V0 p2 > 0. Amxm = V0 −V (p) before output motion. The bubble adds compliance and changes stroke and transient response, but does not prevent static pressure transmission. Physical check The compression law requires absolute pressure; gauge-pressure ratios would give the wrong bubble volume.

Question 7

A trapped bubble consumes stroke before useful motion

A hydraulic line contains a trapped gas bubble of volume V0=2.0cm3V_0=2.0\,\mathrm{cm^3} at absolute pressure p0=100kPap_0=100\,\mathrm{kPa}. The rest of the liquid is incompressible. Before the output can move, line pressure must reach 500kPa500\,\mathrm{kPa} absolute. A master piston of area Am=1.0cm2A_m=1.0\,\mathrm{cm^2} supplies the volume change. Assume isothermal bubble compression, pV=constantpV=\text{constant}.

Diagram shown in the original SVG worksheet.

  1. Find the input travel needed solely to compress the bubble to the lifting threshold.

  2. At that threshold, does the bubble prevent static pressure transmission? Explain the distinction between force transmission and displacement response.

Question 7 - Solution

A trapped bubble consumes stroke before useful motion

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

p0V0=pfVf⇒Vf=100500(2.0)=.400cm3.p_0V_0=p_fV_f\Rightarrow\boxed{V_f=\frac{100}{500}(2.0)=.400\,\mathrm{cm^3}}.ΔV=V0−Vf=1.60cm3.\Delta V=V_0-V_f=1.60\,\mathrm{cm^3}.xm=ΔV/Am=1.60/1.0=1.60cm.\boxed{x_m=\Delta V/A_m=1.60/1.0=1.60\,\mathrm{cm}}.

(b) Result and interpretation

At static equilibrium, gas and liquid share the local pressure. The volume-pressure response isV(p)=p0V0/p,−dVdp=p0V0p2>0.V(p)=p_0V_0/p,\qquad-\frac{dV}{dp}=\frac{p_0V_0}{p^2}>0.Amxm=V0−V(p)before output motion.A_mx_m=V_0-V(p)\quad\text{before output motion}.The bubble adds compliance and changes stroke and transient response, but does not prevent static pressure transmission.

Physical check

The compression law requires absolute pressure; gauge-pressure ratios would give the wrong bubble volume.